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Radda [10]
3 years ago
10

What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67

C
Chemistry
1 answer:
zhenek [66]3 years ago
4 0

Answer: 54 atm

Explanation:

I did 67/82.5 then got 0.8121212121. I them divided 44 by 0.81212121 and got 54.1791044776

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Flauer [41]

Answer:

The boiling point elevation is 3.53 °C

Explanation:

∆Tb = Kb × m

∆Tb is the boiling point elevation of the solution

Kb is the molal boiling point elevation constant of CCl4 = 5.03 °C/m

m is the molality of the solution is given by moles of solute (C9H8O) divided by mass of solvent (CCl4) in kilogram

Moles of solute = mass/MW =

mass = 92.7 mg = 92.7/1000 = 0.0927 g

MW = 132 g/mol

Moles of solute = 0.0927/132 = 7.02×10^-4 mol

Mass of solvent = 1 g = 1/1000 = 0.001 kg

m = 7.02×10^-4 mol ÷ 0.001 kg = 0.702 mol/kg

∆Tb = 5.03 × 0.702 = 3.53 °C (to 2 decimal places)

6 0
3 years ago
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Darina [25.2K]

Answer:

Explanation:

Question 6 options:

1)

A single replacement reaction takes place because sodium is less reactive than hydroxide ions.

7 0
2 years ago
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sammy [17]

Answer:

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...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

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Answer:

Explained below.

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