How do you factorise x^2+22x-103?

What is the appropriate metric unit for measuring the capacity of a water cooler?

Rudiy27

It is probably best to measure a volume of this size in Liters. This is a metric unit. There are 1000 liters in one cubic meter.

6 0

3 years ago

Using technology, we found that Juan’s investment account can be modeled by the function, c(x)=3x2-2x+10, in thousands of dollar

irakobra [83]

The function is $c(x)=3 x^{2} -2x+10$

Initial investment is given when $x=0$ , so substituting this into $c(x)$ we have

$c(0)=3 (0)^{2}-2(0)+10
$
$c(0)=10$

Hence, correct answer is B $10

4 0

4 years ago

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Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar

Digiron [165]

Let the length of the northern side be x and length of the west sides be y. The cost of fence is:
C=10x+10y+5y

and the area enclosed be A=xy
10x+15y=4000
x=400-1.5y
A=400y-1.5y^2
A is maximized when y=400/3 and x=200

8 0

3 years ago

What is the value of x in the equation (x + 12) = (x + 14) – 3?

vodomira [7]

(x + 12) = (x + 14) - 3

subtract 12 from each side

x = x + 14 - 3 - 12

Now if we subtract x from each side we see that x - x = 0. Combine the terms left over and we have -1, so

0 = -1

The answer is NO SOLUTION

6 0

4 years ago

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How do you factorise x^2+22x-103?​

How do you factorise x^2+22x-103?