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mixer [17]
3 years ago
7

Find the change in the force of gravity between two planets when the distance between them becomes 10 times smaller. g

Physics
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

F' = F/16

So, the force of gravity has become 16 times less than initial value.

Explanation:

The force of gravity between two planets, is given by the following formula:

F = Gm₁m₂/r²   ----------- equation 1

where,

F = Force of gravity between two planets

G = Gravitational Constant

m₁ = Mass of one planet

m₂ = Mass of other plant

r = Distance between two planets

Now, if the distance between the planets (r) is 10 times smaller, then Force of gravity will become:

F' = Gm₁m₂/(4r)²

F' = (1/16) (Gm₁m₂/r²)

using equation 1:

<u>F' = F/16</u>

<u>So, the force of gravity has become 16 times less than initial value.</u>

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You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that
ra1l [238]

Answer:

a) I=0.012\ kg.m^2

b) I=0.012\ kg.m^2

Explanation:

Given that:

  • mass of rod, m=0.4\ kg
  • length of the rod, l=0.6\ kg

<u>(a)</u>

<u>Moment of inertia of rod about its center and perpendicular to the rod is given as:</u>

I=\frac{1}{12} m.l^2

I=\frac{1}{12} 0.4\times 0.6^2

I=0.012\ kg.m^2

(b)

<u>Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.</u>

<em>We treat it as two rod with axis of rotation at the end and perpendicular to the plane of rotation. </em>

<em>So, the mass and the length of the rod will become half of initial value.</em>

I=I_1+I_2

I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2

I=2[ \frac{1}{3}\times 0.2\times 0.3^2]

I=0.012\ kg.m^2

7 0
3 years ago
Student 1 and student 2 talk about the speed of the truck
vodka [1.7K]

Answer:

Explanation:

any more explanation?

7 0
3 years ago
What’s the answer for this problem?
pickupchik [31]
The answer is always true a



4 0
3 years ago
Can someone help me with this please...It's Earth Space Science
Andrew [12]
Your answer is correct: Resident 4 would provide the scientist with the most valid results.
3 0
3 years ago
How would the force between two charged particles change if one of the charges were to triple in strength (3x stronger)?
Andreyy89

Answer:

The correct option is (d). "3x stronger".

Explanation:

The force between two charged particle is given by :

F=k\dfrac{q_1q_2}{r^2}

If one charge is tripled, q_1'=3q

New force will be :

F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F

It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.

8 0
3 years ago
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