Answer:
128.9 N
Explanation:
The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

where
F is the force
is the change in momentum
is the time interval
The change in momentum can be written as

where
m = 0.04593 kg is the mass of the ball
u = 0 is the initial velocity of the ball
is the final velocity of the ball
Substituting into the original equation, we find the force exerted on the golf ball:

Answer:
The time taken to stop the box equals 1.33 seconds.
Explanation:
Since frictional force always acts opposite to the motion of the box we can find the acceleration that the force produces using newton's second law of motion as shown below:

Given mass of box = 5.0 kg
Frictional force = 30 N
thus

Now to find the time that the box requires to stop can be calculated by first equation of kinematics
The box will stop when it's final velocity becomes zero

Here acceleration is taken as negative since it opposes the motion of the box since frictional force always opposes motion.
Answer:


Explanation:
Height Of the watermelon when it is dropped is given as

time of fall under gravity

now if water melon start from rest then we have

acceleration due to gravity for watermelon

now we need to find the final speed of watermelon

so we will have


Answer:
<h2>9.39 m/s</h2>
Explanation:
The velocity of the bowling ball can be found by using the formula

p is the momentum
m is the mass
From the question we have

We have the final answer as
<h3>9.39 m/s</h3>
Hope this helps you