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3 years ago

8

What is charging by conduction. Can you also give an real life example of it.

2 answers:

ki77a [65]3 years ago

8 0

To charge by conduction, there must be a physical connection of the charged object to the neutral object. This process can be seen in everyday life, such as cooking on a stove top. Polarization is the process of separating opposite charges within an object.

Vadim26 [7]3 years ago

3 0

Answer: Where the charged object is brought near but never contacted to the object being charged, conduction charging involves making the physical connection of the charged object to the neutral object. Because charging by conduction involves contact, it is often called charging by contact.

Real life example: A positively charged aluminum plate comes into contact with a neutral metal sphere

Explanation:

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3 years ago

A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor

Dima020 [189]

Answer:

Explanation:

Considering Work done by friction is asked

Given

mass of block $m=15.4\ kg$

force $F=182\ N$

inclination $\theta =24^{\circ}$

block is displaced by $s=57.6\ m$

coefficient of kinetic friction $\mu _k=0.135$

Friction force $F_r=\mu _kN$

Normal reaction $N=mg-F\sin \theta =15.4\times 9.8-182\sin (24)$

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3 0

3 years ago

A positively charged particle initially at rest on the ground accelerates upward to 160 m/s in 2.10 s. The particle has a charge

mamaluj [8]

Answer:

The magnitude of the electric field is $8.6\times10^{2}\ N/C$

Explanation:

Given that,

Time t = 2.10 s

Speed = 160 m/s

Specific charge =Ratio of charge to mass = 0.100 C/kg

We need to calculate the acceleration

Using equation of motion

$a=\dfrac{v-u}{t}$

Put the value into the formula

$a=\dfrac{160-0}{2.10}$

$a=76.19\ m/s^2$

We need to calculate the magnitude of the electric field

Using formula of electric field

$E=\dfrac{F}{q}$

$E=\dfrac{ma}{q}$

$E=\dfrac{a+g}{\dfrac{q}{m}}$

Put the value into the formula

$E=\dfrac{76.19+9.8}{0.100}$

$E=8.6\times10^{2}\ N/C$

The direction is upward.

Hence, The magnitude of the electric field is $8.6\times10^{2}\ N/C$

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3 years ago