Let C = cost to rent each chairLet T = cost to rent each table
4C + 8T = 73
2C + 3T = 28
Multiply the 2nd equation by (-2) and then add the equations together
4C + 8T = 73
-4C - 6T = -56
2T = 17T = 17/2 = 8.5
Plug this in to the 1st equation to solve for C
4C + 8(17/2) = 73
4C + 68 = 73
4C = 5C = 5/4 = 1.25
So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50
The answer would be 90 because all you do is add the numbers ! (: pls mark me brainliest
Answer:
C AND D Y=X-3 IS CONNECTING WITH C AND D AND Y=-2X+1 IS CONNECTING WITH A AND C
Step-by-step explanation:
Answer:
The charge for admission is $6 and the charge for each ride is $2
Step-by-step explanation:
Let
x ----> the charge for admission
y ----> the charge for each ride
we have that
-----> equation A
-----> equation B
Solve the system by elimination
Subtract equation B from equation A
Find the value of x
substitute the value of y in any equation
therefore
The charge for admission is $6 and the charge for each ride is $2
