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Brilliant_brown [7]
3 years ago
10

hich equation represents a line that passes through (5, 1) and has a slope of ? y – 5 = (x –1) y – = 5(x –1) y – 1 = (x –5) y –

1 = 5
Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

The equation that would represent it would be y - 1 = (x - 5)

Step-by-step explanation:

In order to get this, we can start with the base form of point-slope form.

y - y1 = m(x - x1)

Now put the point in for (x1, y1)

y - 1 = (x - 5)

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<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

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