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4 years ago

The phase change in which a substance changes from a gas directly to a solid is

2 answers:

7 0

Condensation is the change of the substance from liquid to solid phase. Example of this is the formation of ice. Vaporization is the change of substance from liquid to gas phase. Example of this is the boiling of water. Deposition is the change of a substance from gas to solid phase. Example of this is the formation of ice on a winter day. Sublimation is the change of a substance from solid to gas phase. Example of this is dry ice. The answer is letter C.

ddd [48]4 years ago

5 0

Answer: Properties and States of Matter Practice

1. Which of the following are pure substances? Compounds

2. A substance that cannot be broken into similar substances is called a(n)... Element

3. When a physical change in a sample occurs, which of the following does NOT change? Composition

4. Which of the following will cause a decrease in gas pressure in a closed container? Lowering the temperature

5. The heat of fusion for water is the amount of energy needed for water to... Melt

6. The phase change in which a substance changes from a gas directly to a solid is... Deposition

7. Which of the following phase changes is an exothermic change? sublimation

8. Which of the following has the highest viscosity? Corn Syrup

9. In which of the substances in the figure below are the forces of attraction among the particles so weak that they can be ignored under ordinary conditions? It is the one where the particles are more apart.

Explanation:

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A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising th

LuckyWell [14K]

Answer:

25032.47 W

Explanation:

Power is the time rate of doing work, hence,

P = Work done(non conservative) / time

Work done (non conservative) is given as:

W = total K. E. + total P. E.

Total K. E. = 0.5mv²- 0.5mu²

Where v (final velocity) = 7.0m/s, u (initial velocity) = 0m/s

Total P. E. = mgh(f) - mgh(i)

Where h(f) (final height) = 7.2m, h(i) (initial height) = 0 m

=> W = 0.5mv² - mgh(f)

P = [0.5mv² - mgh(f)] / t

P = [(0.5*790*7²) - (790*9.8*7.2)] / 3

P = (19355 + 55742.4) / 3 = 75097.4/3

P = 25032.47 W

6 0

3 years ago

Name of compounds a. H2Co3 b. NH4OH c.AlPO4 d.NaOH e.AuCI3

seraphim [82]

Answer:

a) Carbonic acid

b) ammonium hydroxide

c) Aluminum phosphate

d) Sodium hydroxide

e) Gold trichloride

Explanation:

I hope this will help you buddy 

3 0

3 years ago

Se debe usar una rampa de 5 m para elevar muebles que pesen 490 N hasta una plataforma a una altura de 2 m. Su propuesta de que

AfilCa [17]

Answer:

F = 180 N

Explanation:

To find the required force you first calculate the angle of the ramp, by using the following relation:

$sin\theta=\frac{2m}{5m}=0.4\\\\\theta=sin^{-1}(0.4)=23.57\°$

Next, you use the Newton second law to know what is the x component (in a rotated coordinate system) of the gravitational force:

$F_x=mgsin\theta$

the required force must be, at least, the last force Fx. You know that the weight of the object is 490N = mg. Hence, you have:

$F=F_x=(450N)sin(23.57\°)=180N$

the required force is 180N

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TRANSLATION:

Para encontrar la fuerza requerida, primero calcule el ángulo de la rampa, utilizando la siguiente relación:

Luego, usa la segunda ley de Newton para saber cuál es el componente x (en un sistema de coordenadas girado) de la fuerza gravitacional:

la fuerza requerida debe ser, al menos, la última fuerza Fx. Sabes que el peso del objeto es 490N = mg. Por lo tanto, tienes:

3 0

3 years ago

When velocity is graphed with respect to time, what does the area under

Juliette [100K]

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

4 0

3 years ago

Read 2 more answers

Can you answer these questions would mean so much grades are due next week and im just really busy will give 35 points

NemiM [27]

Answer:

C.) X-Rays

B.) Focus

A.) Laser

B.) 38 x 10^-16 Joules

4 0

3 years ago