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zvonat [6]
3 years ago
9

Gold has a density of 19.3 g/cm3. I fyou has a 2.00 cm3 block of gold, what would be its mass?

Physics
1 answer:
dalvyx [7]3 years ago
4 0
Density equals mass × volume

d=m/V

then m=d×V=19.3×2=38.6g

m=38.6g

hope this helps you
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Answer:

1.52g

Explanation:

Given parameters:

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Mass combined  = 82kg

Unknown:

Acceleration of the bicycle  = ?

Solution:

From Newton second law of motion suggests that:

   Force = mass x acceleration

  Acceleration = \frac{force}{mass}  = \frac{125}{82}   = 1.52g

8 0
3 years ago
In a science fiction story, a microscopic black hole is given an enormous positive charge by firing an un-neutralized ion drive
Olegator [25]

Answer: distance d = 4.73e10m

Explanation: Suppose the charge on the black hole is 5740 C which is a positive charge.

Using electric potential V formula:

V = kq / d

Where K = 9.05×10^9Nm^2/C

And e = 1.6×10^-19C

But you don't need to substitute it.

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d = 4.73e10 m

6 0
3 years ago
Electric Circuits Homework
nirvana33 [79]
<h2>Sorry, But I don't know!!</h2>
3 0
2 years ago
A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
Arada [10]

Explanation:

The given data is as follows.

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   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

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And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

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Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
3 years ago
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seraphim [82]

A device employing a lens, shutter, and persistent light source that projects images from glass slides onto a flat white wall or cloth drape hung in the dark is image projection began with the MAGIC LANTERN

<h3><u>Explanation:</u></h3>

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The photos and images that are taken can be increased in the size and projection can be made. These images can be enlarged in size by the help of a photographic images. this helps in image and also in taking photographs. This photographic image can be attached with Magic lantern. A long slide of glass helps in projecting the image on the walls or cloth drapes using magic lantern. This gives life to Shadows.

6 0
3 years ago
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