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Dafna1 [17]
3 years ago
13

What are two ways the Doppler effect can be applied in everyday life?

Physics
1 answer:
Mekhanik [1.2K]3 years ago
3 0
Two ways the Doppler effect can be applied to every day life is...
1. The pitch of an Ambulance Siren shifts as it passes you. 
<span>2. A cop's radar gun using radiation waves to find out how fast your going as you confused I-85 with the speed limit</span>
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The Statue of Liberty is made of copper that has turned green because it had undergone a change. What can be said about this cha
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D. because the statue has a new chemical called patina. It is no longer copper.
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3 years ago
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Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an
8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 m/s^2 where as radial the component of acceleration is 8.77 m/s^2

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

r=e^u

So the transverse component of acceleration are given as

a_{\theta}=(ru''+2r'u')\\

Here

r=e^u\\r=e^{\pi/4}\\r=2.1932 m

r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m

So

a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\

The transverse component of acceleration is 26.32 m/s^2

The radial component is given as

a_r=r''-r\theta'^2

Here

r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m

So

a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2

The radial component of acceleration is 8.77 m/s^2

6 0
3 years ago
When bill butcher of port city brews discusses shelf space and the way that a merger could increase the leverage potential of la
lozanna [386]

He is discussing Bargaining Power of Buyers competitive force.

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The employment of various financial instruments or borrowed cash, or leverage, is an investing strategy that aims to improve an investment's potential return. The level of debt a company utilizes to finance its assets is another definition of leverage.

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To learn more about  leverage, visit:   brainly.com/question/14230485

#SPJ4

6 0
1 year ago
A motor running at 2600 rev/min is suddenly switched off and decelerates uniformly to rest after 10 s. Find the angular decelera
Mama L [17]
Angular acceleration = (change in angular speed) / (time for the change)

change in angular speed = (zero - 2,600 RPM)  =  -2,600 RPM

time for the change = 10 sec

Angular acceleration = -2600 RPM / 10 sec = -260 rev / min-sec

(-260 rev/min-sec) x (1 min / 60 sec) = <em>-(4 1/3)  rev / sec²</em>

Since the acceleration is negative, the motor is slowing down.
You might call that a 'deceleration' of (4 1/3) rev/sec² .

The average speed is  1/2(2,600 + 0) = 1,300 rev/min = (21 2/3) rev/sec.

Number of revs = (average speed) x (time) = (21 2/3) x (10sec) = <em>(216 2/3) revs</em>
6 0
4 years ago
A toroid has a square cross section with the length of an edge equal to the radius of the inner surface. The ratio of the magnit
Tasya [4]

Answer:

2

Explanation:

7 0
3 years ago
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