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makvit [3.9K]
3 years ago
15

A train is traveling at 30.0 m/sm/s relative to the ground in still air. The frequency of the note emitted by the train whistle

is 262 HzHz. The speed of sound in air should be taken as 344 m/sm/s. Part A What frequency fapproachfapproachf_approach is heard by a passenger on a train moving at a speed of 18.0 m/sm/s relative to the ground in a direction opposite to the first train and approaching it
Physics
1 answer:
REY [17]3 years ago
3 0

Answer:

Explanation:

The problem is based on Doppler's effect , for which expression is as follows

n = \frac{n_o(V+v_o)}{(V-v_s)}

n is apparent frequency , n₀ is original frequency , V is velocity of light , v₀ is velocity of observer and v_s is velocity of source , both coming towards each other.

Putting the values

n = \frac{262(344+18)}{(344-30)}

n = 302 .

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Answer:

Explanation:

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t=2USinθ/g

Therefore,

R=Ux.t

R=UCosθ.2USinθ/g

R=U^2×2SinθCosθ/g

Then, from trigonometric ratio

2SinθCosθ= Sin2θ

R=U^2Sin2θ/g

Given that θ=32° and g=9.81m/s^2

Then

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The box is at a distance A from the point of projection. Then the range R=A

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A=0.0916U^2

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U^2=10.915A

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U=√10.915A

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8 0
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What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force
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Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it trie
sammy [17]

Answer:

2.64 m/s

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Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna

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