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3 years ago

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Which statement is true about molarity and percent by mass?

2 answers:

Serga [27]3 years ago

8 0

<h3>The answer is D, They are different units of concentration. </h3>

Triss [41]3 years ago

5 0

Answer : The correct option is, They are different units of concentration.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula of molarity :

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in liters}}$

Mass percent : It is defined as the mass of solute present in the mass of solution.

Formula of mass percent :

$\text{Mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

Hence, both are the different unit of concentration.

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It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the elec

babymother [125]

Answer:

Their electrons are placed in a higher number of orbitals

Explanation:

Suppose a element be Ga .

The atomic no is 31

The configuration is given by

$\\ \sf\longmapsto 1s^22s^22p^63ss^23p^63d^{10}4s^24p^1$

Or

$\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1$

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3 years ago

Use the periodic table to calculate the molar mass of each of the following compounds. Give your answer to the correct number of

Musya8 [376]

1) Answer is: molar mas of ammonia is 17.031 g/mol.

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M(NH₃) = 14.007 + 3 · 1.008 · g/mol.

M(NH₃) = 17.031 g/mol.

2) Answer is: molar mas of lead(II) chloride is 278.106 g/mol.

M(PbCl₂) = Ar(Pb) + 2 · Ar(Cl) · g/mol.

M(PbCl₂) = 207.2 + 2 · 35.453 · g/mol.

M(PbCl₂) = 278.106 g/mol.

3) Answer is: molar mas of acetic acid is 60.052 g/mol.

M(CH₃COOH) = 2 · Ar(C) + 2 · Ar(O) + 4 · Ar(H) · g/mol.

M(CH₃COOH) = 2 · 12.0107 + 2 · 15.9994 + 4 · 1.008 · g/mol.

M(CH₃COOH) = 60.052 g/mol.

5 0

4 years ago

Read 2 more answers

High energy waves have long wavelengths and low frequencies. long wavelengths and high frequencies. short wavelengths and low fr

creativ13 [48]

High energy waves have short wavelengths and thus high frequencies as a result.

5 0

3 years ago

Read 2 more answers

Number of moles in 145.7 g of squaric acid

Nesterboy [21]

To find moles : moles= Mass (C₄H₂O₄) / RFM (C₄H₂O₄)

so moles = 147.7 / 114 = <span>1.2956mol

hope that helps </span>

3 0

3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

3 years ago