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pantera1 [17]
4 years ago
11

Use the periodic table to calculate the molar mass of each of the following compounds. Give your answer to the correct number of

significant figures. Ammonia (NH3): g/mol Lead(II) chloride (PbCl2): g/mol Acetic acid (CH3COOH): g/mol
Chemistry
2 answers:
Sveta_85 [38]4 years ago
7 0
<span><span>Ammonia (NH3): </span> ⇒ 17.04 g/mol</span><span><span>Lead(II) chloride (PbCl2): </span> ⇒ 278.10 g/mol</span>

<span><span>Acetic acid (CH3COOH): </span> ⇒ 60.06<span> g/mol</span></span>
Musya8 [376]4 years ago
5 0

1) Answer is: molar mas of ammonia is 17.031 g/mol.

M(NH₃) = Ar(N) + 3 · Ar(H) · g/mol.

M(NH₃) = 14.007 + 3 · 1.008 · g/mol.

M(NH₃) = 17.031 g/mol.

2) Answer is: molar mas of lead(II) chloride is 278.106 g/mol.

M(PbCl₂) = Ar(Pb) + 2 · Ar(Cl) · g/mol.

M(PbCl₂) = 207.2 + 2 · 35.453 · g/mol.

M(PbCl₂) = 278.106 g/mol.

3) Answer is: molar mas of acetic acid is 60.052 g/mol.

M(CH₃COOH) = 2 · Ar(C) + 2 · Ar(O) + 4 · Ar(H) · g/mol.

M(CH₃COOH) = 2 · 12.0107 + 2 · 15.9994 + 4 · 1.008 · g/mol.

M(CH₃COOH) = 60.052 g/mol.

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CaSO4 + AlBr3 &gt; CaBr2 +Al2(SO4)3 What will the coefficient of CaBr2 when the equation is balanced using the smallest possible
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Answer:

3 will be the correct coefficient of CaBr2

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In balancing a chemical equation, numbers should be assigned to both reactants and products as a numerical coefficients until all atoms of elements in both sides of the equation count equal.

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Looking at the unbalanced equation in the question, in the product Al2(SO4)3 there are 3 SO4 group. This will warrant putting 3 behind CaSO4 in order to balance the atoms of SO4 group. That operation will automatically put the number of Ca atoms in CaSO4 to be 3 therefore making CaBr2 to have 3 coefficient as in the balanced equation. This is to balance the number of Ca atoms in both sides to be 3.

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