Answer:
B
Explanation:
The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither <u><em>created</em></u> nor <u><em>destroyed</em></u> in chemical reactions. If we account for all reactants and products in a chemical reaction, the total mass will be the same at any point in time in any closed system.
Answer:
Explanation:
When looking at a chemical reaction, the substance present before the reaction takes place are called the (5)
REACTANT
and the substance produced after the reaction are the (6).
PRODUCT
know through the Law of Conservation of (7)
MATTER
that nothing is created or destroyed. This is reflected in a (8
BALANCED
chemical equation, where the NUMBER OF atoms of each element on each side of the arrow is (9)-
equal
or the same.
REMEMBER: WHEN BALANCING EQUATIONS YOU CANNOT CHANGE THE SUBSCRIPTS OF THE COMPOUNDS, YOU CAN ONLY SHOW BY THE COEFFICIENTS HOW MANY MOLECULES YOU HAVE!
An organism that is able to form nutritional organic substances from simple inorganic substances such as carbon dioxide.
Answer:
3 will be the correct coefficient of CaBr2
Explanation:
In balancing a chemical equation, numbers should be assigned to both reactants and products as a numerical coefficients until all atoms of elements in both sides of the equation count equal.
The balanced equation of the reaction will be:
3CaSO4 + 2AlBr3 ==> 3CaBr2 + Al2(SO4)3
Looking at the unbalanced equation in the question, in the product Al2(SO4)3 there are 3 SO4 group. This will warrant putting 3 behind CaSO4 in order to balance the atoms of SO4 group. That operation will automatically put the number of Ca atoms in CaSO4 to be 3 therefore making CaBr2 to have 3 coefficient as in the balanced equation. This is to balance the number of Ca atoms in both sides to be 3.
Answer:16.22L
Explanation:
Mass of CO2=28.8g
Molar mass of CO2=44.00964g/mol
No of moles (n) = mass(g)/molar mass(g/mol)
= 28.8g/44.00964g = 0.6544mol
From the ideal gas formula
PV=nRT
V=nRT/P
Where n=0.6544mol
R=62.363LmmHg/Kmol
T=22+273=295K
V=0.6544x62.3636x295/742
=16.22L