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Ksivusya [100]
3 years ago
7

Please help

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

Bro im having the same prob

Step-by-step explanation:

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PLEASE HELP!!! 100 POINTS!
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Answer:

  x = 0; y = -6; z = 1

Step-by-step explanation:

You want to find the solution to the system of equations ...

  • 9x+y-3z=-9
  • 10x-y+2z=8
  • -10x-y+4z=10

<h3>Solution</h3>

This set of equations is conveniently solved using the matrix row-reduction features of a scientific or graphing calculator, spreadsheet, or any of a number of apps or on-line calculators.

The attachment shows the solution to be ...

  (x, y, z) = (0, -6, 1)

__

<em>Additional comment</em>

Solving a system of three or more equations "by hand" often can be done by an ad hoc process. It can be done in systematic fashion using Gauss-Jordan reduction techniques, but that often gets messy. Similarly, Cramer's Rule can be used, but that math tends to involve more arithmetic operations than are really necessary.

Adding the first equation to the other two eliminates the y-variable and reduces the system to two equations in two unknowns.

  (9x +y -3z) +(10x -y +2z) = (-9) +(8) . . . . adding [1] and [2]

  19x -z = -1 . . . . simplified

  (9x +y -3z) +(-10x -y +4z) = (-9) +(10) . . . . adding [1] and [3]

  -x +z = 1 . . . . simplified

At this point, we could graph the two equations, or we can proceed algebraically.

Adding these two equations gives ...

  (19x -z) +(-x +z) = (-1) +(1)

  18x = 0   ⇒   x = 0

Using the second of the reduced equations, we find ...

 -x +z = 1

  0 +z = 1   ⇒   z = 1

And using the second of the original equations, gives us ...

  10(0) -y +2(1) = 8

  -y = 6 . . . . . subtract 2

  y = -6 . . . . multiply by -1

Then the solution is (x, y, z) = (0, -6, 1), as above.

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\rightarrow \cos^{2}(2x)-\sin^{2}(2x)=\cos^{2}(2x)-\sin^{2}(2x)
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Answer:

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Step-by-step explanation:

The computation of the volume of the prism is shown below:

As we know that

Volume of the prism is

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hence, the first option is correct

And, the rest of the options are wrong

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