Answer:
log₄ 10 = log₁₀ 10 / log₁₀ 4
Step-by-step explanation:
Taking the x to be a power then;
Introduce log on both sides
x log 4= log 10
x= log 10/log 4
log₄ 10 = log₁₀ 10 / log₁₀ 4
Answer:
21
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Starting with 7,000, after 0 years there will be no increase so you still have 7,000.
The fist year you increase by 5% of 7,000.
.05x7000=350
You have a 350 increase, add that to the original 7000 to find the actual population after 1 year (domain value 1).
After 1 year: 7350
For year 2 there is an increase of 5% again, only this time we find 5% of 7350 since that was the previous years population.
.05x7350=368
Add that to previous population.
368+7350=7718
At this point so far the yearly populations have been (7000, 7350, 7718)
Answer choice B is the only one to have this progression.
Answer:
in 13.95 years the senior class will have 100 students.
Step-by-step explanation:
P(h) = p(0.92)^t (equation for exponential change)
P(h) - population of highschool (or senior class) = 100
p - staring amount = 320
t = time in years
100 = 320(0.92)^t
1/3.2 = .92^t (divide both sides by 320)
log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)
13.9497 = t
