I think these are the correct answers! I'm currently rechecking them and thought I would post this while I recheck the answers so that way you at least have something to go off of.
Na^+1 and o^-2:
Anion name - Oxide
Compound formula - Nao
Compound name - dioxygen
Na^+1 and N^-3:
Cation name - Sodium
Anion name - Nitride
Compound formula - Na3N (3 is in subscript)
Compound name - Sodium nitride
K^+1 and Br^1:
Cation name - Potassium
Anion name - Bromide
Compound formula - KBr
Compound name - Potassium Bromide
K^+1 and N^-3:
Cation name - Potassium
Anion name - Nitride
Compound formula - KNO2 (2 is in subscript)
Compound name - Potassium Nitride
Li^+1 and I^-1:
Cation name - Lithium
Anion name - lodide
Compound formula - LiI
Compound name - Lithium iodide
Li^+1 and O^-2:
Cation name - Lithium
Anion name - Oxide
Compound formula - Li2O (2 is in subscript)
Compound name - Lithium oxide
Li^+1 and N^-3:
Cation name - Lithium
Anion name - Nitride
Compound formula - Li3N
Compound name - Lithium Nitride
Mg^+2 and Cl^-1
Cation name - Magnesium
Anion name - Dichloride
Compound formula - MgCl2
Compound name - Magnesium dichloride
It would go B. A. E. D. C.
Hope I helped!
Your answer is :
P = K * x where P is partial pressure K is Henry's constant and x is solubility
<span>775 torr = K L·torr/mol * 0.0.0347 mole / liter </span>
<span>K = 775 / 0.0347 = 22334 L·torr/mol </span>
<span>in the second solution we have </span>
<span>1670 = 22334 * x </span>
<span>x = 1670 / 22334 </span>
<span>= 0.075 moles CO2 per liter of water.
</span>
Hope this helps :)
If you need anymore help with questions then feel free to ask me :D
the answer is twenty eight
Answer:
The answer is D. 0.60 L
Explanation:
The balanced reaction equation including states of matter is;
H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)
More simple:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Now, we can see from this reaction equation that the mole ratio of NaOH to H2SO4 is 2:1
Number of moles of H2SO4 reacted = 1.2 moles
Hence;
2 moles of NaOH reacts with 1 mole of H2SO4
x moles of NaOH reacts with 1.2 moles of H2SO4
x = 2 * 1.2/1 = 2.4 moles of NaOH
Recall that;
Number of moles = Concentration * Volume
Volume = number of moles/concentration
Volume of NaOH is obtained from;
Volume = 2.4 moles/ 4.0 M
Volume = 0.60 L