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Svetradugi [14.3K]
4 years ago
14

There are two main characters of matter:

Chemistry
1 answer:
Oksana_A [137]4 years ago
3 0
Mass and weight are the 2 main characters of matter
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What does a high melting point temperature indicate about a substance?
Lilit [14]
They have strong intermolecular forces between their atoms, hence why more heat is necessary.
3 0
3 years ago
Read 2 more answers
PLEASE HELP, I REALLY NEED HELP WITH THIS!!!​
Mkey [24]

Answer:

Explanation:

There are 6 32S atoms and 2 36S atoms

Their respective contributions to the average aomic mass is (6*32)=192, and (2*36)=72.  Added together, this makes 264 total.  Divide by the total number of atoms, 8.  (264/8) = 33.00

The weighted atomic mass of these S atoms is 33.00 amu (atomic mass units)

3 0
3 years ago
Calculate the unit cell edge length for an 85 wt% fe-15 wt% v alloy. All of the vanadium is in solid solution, and, at room temp
Lady bird [3.3K]

Answer is 0.289nm.

Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.

wt % of Fe in Fe-V alloy = 85%

wt % of V in Fe-V alloy = 15%

We need to calculate edge length of the unit cell having bcc structure.

Using density formula,

\rho_{ave}=\frac{Z\times M_{ave}}{a^3\times N_A}

For calculating edge length,

a=(\frac{Z\times M_{ave}}{\rho_{ave}\times N_A})^{1/3}

For calculating M_{ave}, we use the formula

M_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{V}}{M_V}}

Similarly for calculating (\rho)_{ave}, we use the formula

\rho_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{\rho_{Fe}}+\frac{(wt\%)_{V}}{\rho_V}}

From the periodic table, masses of the two elements can be written

M_{Fe}= 55.85g/mol

M_{V}=50.941g/mol

Specific density of both the elements are

(\rho)_{Fe}=7.874g/cm^3\\(\rho)_{V}=6.10g/cm^3

Putting  M_{ave} and \rho_{ave} formula's in edge length formula, we get

a=\left [\frac{Z\left (\frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{Fe}}{M_{Fe}}}  \right )}{N_A\left (\frac{100}{\frac{(wt\%)_V}{\rho_V}+\frac{(wt\%)_V}{\rho_V}}  \right )}  \right ]^{1/3}

a=\left [\frac{2atoms/\text{unit cell}\left (\frac{100}{\frac{85\%}{55.85g/mol}+\frac{15\%}{50.941g/mol}}  \right )}{(6.023\times10^{23}atoms/mol)\left (\frac{100}{\frac{85\%}{7.874g/cm^3}+\frac{15\%}{6.10g/cm^3}}  \right )}  \right ]^{1/3}

By calculating, we get

a=2.89\times10^{-8}cm=0.289nm

7 0
3 years ago
TRUE OR FALSE : The aim of an experiment can often tell us which variable is the independent variable and which variable is the
abruzzese [7]

Answer:

True

Explanation:The whole point of and expirement is to test the indepedent variable and the outcom or what your measuring is the dependent

sorry for the tone its late where i live

7 0
3 years ago
Вычислить равновесные концентрации частиц в растворе, содержащем 0,01 моль/л Cu(NO3)2 и 1,0 моль/л NH3.
Wewaii [24]

Answer:

i dOnT SpEaK uR lAnGuAgE

Explanation:

ReEEEeEeEeEeEeEeEeEeeEEEeeeeEEEEeeeeeEEeEEeeeeeEEEEEeeeEee

3 0
3 years ago
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