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kobusy [5.1K]
3 years ago
9

NEED HELP ASAP!!! I just need to know the order

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
7 0
4 Movement of less dense material
3 Heating of cooler material
1 cooling of warmer material
2 movement of denser material
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How can we increase the rate of collisions between the reactants in this reaction? mg 2hcl → mgcl2 h2
Minchanka [31]

<u>The frequency of </u><u>collisions </u><u>between the two reactants increases as the </u><u>concentration </u><u>of the reactants increases</u>. When collisions happen, they don't always cause a reaction (atoms misaligned or insufficient energy, etc.). Higher concentrations result in more collisions and reaction opportunities.

Increasing a reactant's surface area increases the frequency of collisions and thus the reaction rate. The surface area of several smaller particles is greater than that of a single large particle. The greater the available surface area for particles to collide, the faster the reaction will occur.

<h3>How does concentration affect the rate of collisions between reactants?</h3>

Thus, we can conclude that by increasing the concentration of Mg in the reaction mixture we increase the rate of collisions between the reactants in this reaction.

<h3>What does the half reaction of an oxidation-reduction reaction show?</h3>

Iron gains electrons in the half reaction of an oxidation-reduction reaction. What does iron's electron gain mean? It has been reduced. Predict the product that will precipitate out of the reaction using the solubility rules and the periodic table.

Learn more about collisions of particles:

brainly.com/question/14897392

#SPJ4

4 0
2 years ago
A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and y_{C-6} and y_{N_2} are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Q=-40036+(-672.21)=-40708.21J

Finally we convert this result to kJ:

Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

Learn more:

  • brainly.com/question/25475410
  • brainly.com/question/12625048
6 0
2 years ago
Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the
prohojiy [21]

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

3 0
3 years ago
What is the smallest halogen atom<br>​
ad-work [718]
The smallest halogen atom is fluorine
4 0
3 years ago
Read 2 more answers
a graduated cylinder has 35.0 mL of water in it before an object is dropped inside. the new volume is 38.5 mL. What is the volum
tino4ka555 [31]
Displaced volume:

final volume - initial volume

1 mL = 1 cm³

38.5 mL - 35.0 mL = 3.5 cm³

hope this helps!
4 0
3 years ago
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