All categories

3 years ago

I WILL GIVE BRAINLIEST!

Chemistry

2 answers:

stira [4]3 years ago

7 0

The correct answer is option a, that is, they produce ions when dissolved in water.

The acids and bases refer to the chemical components, which reacts with water. The molecules of acids dissociate to give hydrogen ions to water, while the bases dissociate to provide hydroxide ions to the water, or that takes hydrogen ions from water and leave the hydroxide ions behind.

Ann [662]3 years ago

6 0

Answer:

They produce ions when dissolved in water

Explanation:

You might be interested in

True or False Water particles move with the waves.

g100num [7]

The answer would be , True

8 0

3 years ago

What 3 sub types of covergent plate boundaries?

Virty [35]

(1) Ocean to Continent
(2)Continent to Continent
(3)Ocean to Ocean
are the three sub types of convergent plate boundaries.

5 0

3 years ago

When two monosaccharides condense to form a disaccharide, what is the other product of the reaction? enter the molecular formula

koban [17]

When two monosaccharides combine to make a disaccharide, water is the byproduct.

<h3>What are monosaccharides ?</h3>

The most fundamental building blocks from which all carbohydrates are constructed are monosaccharides, commonly known as simple sugars. They are the most basic types of sugar. They are typically crystalline solids, colorless, and soluble in water.

These three monosaccharides—glucose, fructose, and galactose—are crucial for nutrition. Six carbon atoms, twelve hydrogen atoms, and six oxygen atoms make up each single sugar molecule.

To learn more about monosaccharides from the given link:

brainly.com/question/13416862

#SPJ4

4 0

1 year ago

The names of the components FeS, NaCl, and Al(3)O(2) all end in the suffix.

anastassius [24]

Answer:

A) -ide

Explanation:

FeS = iron(II) sulfide or ferrous sulfide

NaCl = Sodium chloride

Al(3)O(2) = Aluminium oxide

3 0

3 years ago

25.0cm3 of s saturated potassium hydroxide is neutralized by 35.0cm3 of hydrogen chloride acid of concentration 0.75 mol/dm3. Ca

Kamila [148]

Answer:

Concentration of the original $\rm KOH$ solution: approximately $1.05\; \rm mol \cdot dm^{-3}$ .

Explanation:

Notice that the concentration of the $\rm HCl$ solution is in the unit $\rm mol\cdot dm^{-3}$ . However, the unit of the two volumes is $\rm cm^{3}$ . Convert the unit of the two volumes to $\rm dm^{3}$ to match the unit of concentration.

$\begin{aligned} V(\mathrm{NaOH}) &= 25.0\; \rm cm^{3} \\ &= 25.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0250\; \rm dm^{3} \end{aligned}$ .

$\begin{aligned} V(\mathrm{HCl}) &= 35.0\; \rm cm^{3} \\ &= 35.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0350\; \rm dm^{3} \end{aligned}$ .

Calculate the number of moles of $\rm HCl$ molecules in that $0.0350\; \rm dm^{3}$ of $0.75\; \rm mol \cdot dm^{3}$ $\rm HCl\!$ solution:

$\begin{aligned}n(\mathrm{HCl}) &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.00350\; \rm dm^{3} \times 0.75\; \rm mol \cdot dm^{3} \\ &\approx 0.02625\; \rm mol\end{aligned}$ .

$\rm HCl$ is a monoprotic acid. In other words, each $\rm HCl\!$ would release up to one proton $\rm H^{+}$ .

On the other hand, $\rm KOH$ is a monoprotic base. Each $\rm KOH\!$ formula unit would react with up to one $\rm H^{+}$ .

Hence, $\rm HCl$ molecules and $\rm KOH\!$ formula units would react at a one-to-one ratio.

${\rm HCl}\, (aq) + {\rm NaOH}\, (aq) \to {\rm NaCl}\, (aq) + {\rm H_2O}\, (l)$ .

Therefore, that $0.02625\; \rm mol$ of $\rm HCl$ molecules would neutralize exactly the same number of $\rm NaOH$ formula units. That is: $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ .

Calculate the concentration of a $\rm NaOH$ solution where $V(\mathrm{NaOH}) = 0.0250\; \rm dm^{3}$ and $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ :

$\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} \\ &= \frac{0.02625\; \rm mol}{0.0250\; \rm dm^{3}}\approx 1.05\; \rm mol \cdot dm^{-3}\end{aligned}$ .

7 0

3 years ago