Marco is looking for a used sports car,

Sam runs 9 kilometers in 2.5 hours. what is his speed?

svp [43]

Considering the definition of speed, the speed of Sam is 3.6 $\frac{km}{h}$ .

<h3>Definition of speed</h3>

Speed is a quantity that expresses the relationship between the space traveled by an object. That is, the speed is associated with the change of position of an object in space within a certain amount of time.

The speed can be calculated using the expression:

$speed= \frac{displacement}{time}$

<h3>Speed of Sam</h3>

In this case, you know:

displacement= 9 km
time= 2.5 h

Replacing in the definition of speed:

$speed= \frac{9 km}{2.5 h}$

Solving:

<u><em>speed= 3.6 </em></u> $\frac{km}{h}$

Finally, the speed of Sam is 3.6 $\frac{km}{h}$ .

Learn more about speed:

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brainly.com/question/20725831

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3 0

2 years ago

Identifying Mechanical Energy

arsen [322]

Bruh ima be honest with you idek

3 0

4 years ago

Read 2 more answers

according to isaac newtons theory of gravitation the force exerted between two objects is dependent on- A- an objects weight. B-

puteri [66]

A an objects weight hope this helps! :D

3 0

3 years ago

A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this

kondaur [170]

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{402}{603}$

$\lambda = 0.67\ m$

Number of anti nodes in the standing wave

$n=\dfrac{l}{\frac{\lambda}{2}}$

$n=\dfrac{2l}{\lambda}$

$n=\dfrac{2\times 1.33}{0.67}$

n =3.97= 4.

Number of antinodes is equal to 4.

7 0

3 years ago

2. A 200.0-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and th

Neporo4naja [7]

Answer: 1960 N

Explanation:

The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:

$F_{net}=ma=0$

There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:

$F_{net}=W-F_f=0$

From the previous equation, we find that the frictional force is equal to the weight of the bear:

$F_f=W=mg=(200.0 kg)(9.8 m/s^2)=1960 N$

8 0

3 years ago