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nikklg [1K]
3 years ago
5

A fugitive tries to hop on a freight train traveling at a constant speed of 5.2 m/s . Just as an empty box car passes him, the f

ugitive starts from rest and accelerates at a = 1.3 m/s2 to his maximum speed of 6.1 m/s , which he then maintains. How long does it take him to catch up to the empty box car? What is the distance traveled to reach the box car? Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
RSB [31]3 years ago
6 0

Answer:

16 seconds

97 m

Explanation:

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{6.1-0}{1.3}\\\Rightarrow t=4.692\ s

Train has moved a distance of 5.2\times 4.692=24.3984\ m

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 1.3\times 4.692^2\\\Rightarrow s=14.3096\ m

Fugitive needs to run 24.3984-14.3096=10.0888\ m to make up

Relative speed of fugitive 6.1-5.2=0.9\ m/s

Time taken

t=\dfrac{10.0888}{0.9}\\\Rightarrow t=11.209\ s

Time taken to catch the box = 4.692+11.209 = 15.901 seconds = 16 seconds

Distance traveled by the fugitive = 6.1\times 15.901=96.9961\approx 97\ m

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Suppose that 2 scientists use different measurement systems in their work. What problems might arise if they shared their data?
bixtya [17]
<span>In assumption that there were two scientists who used different measurement systems in their research. The problems that might arise if they shared their data is obviously and primarily error. Errors are recognized and one element in every measure, system and quantity. Error was already even present in the measurement system alone a scientist used and it will furthermore aggregate, when these two different scales are combined the more error escalates in the process. There are two types: random and systematic error.   </span>



8 0
3 years ago
A pendulum is formed by taking a 2.0 kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. it is
Lera25 [3.4K]

Answer: 1.39 s

Explanation:

We can solve this problem with the following equations:

\frac{\Delta l}{l_{o}}=\frac{F}{AY} (1)

T=2 \pi \sqrt{\frac{l_{o}}{g}} (2)

Where:

\Delta l=0.05 mm=5(10)^{-5} m is the length the steel wire streches (taking into account 1mm=0.001 m)

l_{o} is the length of the steel wire before being streched

F=mg=(2 kg)(9.8 m/s^{2})=19.6 N is the force due gravity (the weight) acting on the pendulum with mass m=2 kg

A is the transversal area of the wire

Y=2(10)^{11} Pa is the Young modulus for steel

T is the period of the pendulum

g=9.8 m/s^{2} is the acceleration due gravity

Knowing this, let's begin by finding A:

A=\pi r^{2}=\pi (\frac{d}{2})^{2}=\pi \frac{d^{2}}{4} (3)

Where d=1.1 mm=0.0011 m is the diameter of the wire

A=\pi \frac{(0.0011 m)^{2}}{4} (4)

A=9.5(10)^{-7}m^{2} (5)

Knowing this area we can isolate l_{o} from (1):

l_{o}=\frac{\Delta l AY}{F} (6)

And substitute l_{o} in (2):

T=2 \pi \sqrt{\frac{\frac{\Delta l AY}{F}}{g}} (7)

T=2 \pi \sqrt{\frac{\frac{(5(10)^{-5} m)(9.5(10)^{-7}m^{2})(2(10)^{11} Pa)}{2(10)^{11} Pa}}{9.8 m/s^{2}}} (8)

Finally:

T=1.39 s

3 0
3 years ago
A weatherman carried an aneroid barometer from the ground floor to his office atop the Sears Tower in Chicago. On the level grou
Sophie [7]

Answer:

442.36038 m or 1451.31362 ft

Explanation:

P_1 = Initial pressure = 30.15 inHg

P_2 = Final pressure = 28.607 inHg

\rho = Density of air  = 0.075 lb/ft³

1\ lb/ft^3=16.0185\ kg/m^3

1\ in=0.0254\ m

1\ m=3.28084\ ft

Density of mercury = 13560 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Difference in pressure is given by

P_1-P_2=\rho gh\\\Rightarrow h=\frac{P_1-P_2}{\rho g}\\\Rightarrow h=\frac{(30.15-28.607)\times 13560\times 0.0254\times 9.81}{0.075\times 16.0185\times 9.81}\\\Rightarrow h=442.36038\ m\\\Rightarrow h=442.36038\times 3.28084\\\Rightarrow h=1451.31362\ ft

The height of the building is 442.36038 m or 1451.31362 ft

4 0
2 years ago
A newton-meter is a measure of work also known as the _____.
MatroZZZ [7]
1 newton-meter is 1 Joule, the unit of work and energy.
4 0
3 years ago
Which elements will bond ionically with barium such that the formula would be written as BaX2? A) Nitrogen, chlorine, and sodium
erma4kov [3.2K]

The answer would be:

B. Chlorine, iodine and Fluorine

Barium has 2 valence electrons. To satisfy the BaX₂ , this would mean that Barium will need to give one of each of its electrons. The elements that need 1 electron would be those that have 7 valence electrons to complete the octet. These elements would fall in group 7 or halogens. Chlorine, iodine and fluorine are all in Group 7, so this would be the best choice.

7 0
3 years ago
Read 2 more answers
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