Answer:
The equation of a line parallel to 3x - y= -2 and passes through the point (0, -3) is -3x + y + 3 = 0
Step-by-step explanation:
Here , the given equation of line 1 : 3x - y= -2
The Slope form of the equation is y = m x + c
⇒3x + 2 = y , where m = 3 is the slope for the line 1
Now, as the Line 2 is parallel to Line 1,
Slope of Line 1 (m1) = Slope of Line 1 (m2)
Hence, the slope of line 2 = 3
Now, by POINT SLOPE FORMULA
The equation of line with point (x0, y0) is given as
(y - y0) = m (x - x0)
⇒ For the point (0,-3) the equation of Line 2 is:
y - (-3) = 3 ( x-0)
or, y + 3 = 3x ⇒ -3x + y + 3 = 0
Hence, the equation of a line parallel to 3x - y= -2 and passes through the point (0, -3) is -3x + y + 3 = 0
