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irakobra [83]
3 years ago
5

Given the expression −10p2q + 7p3q − 5q

Mathematics
1 answer:
kaheart [24]3 years ago
6 0

Answer:

pq-5q or q(p-5)

Step-by-step explanation:

-10p2q+7p3q-5q=-20pq+21pq-5q=pq-5q=q(p-5)

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x = 3 or x = 1

note that log 5 is usually taken to mean log_{10} 5

using the law of logarithms

logx - logy = log (\frac{x}{y})

the right hand side can be expressed as

log 10000 - log 16 = log (\frac{10000}{16}) = log 625

divide both sides by log 5

x² - 4x + 7 = \frac{log625}{log5} = 4

subtract 4 from both sides

x² - 4x + 3 = 0 ← in standard form

(x - 3 )(x - 1) = 0

equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 1 = 0 ⇒ x = 1


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