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gulaghasi [49]
3 years ago
6

an athlete runs 8 miles from their house to the store on a path. the athlete then runs to a point m miles from their house on th

e same path. the athlete decides to finish the run by returning to the store. the athlete ran a total of 16 miles. formulate an absolute value equation to represent this situation. then solve the equation.
Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
9. Which of the following is a mental benefit of exercise
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Find the values of x and y for which the quadrilateral must be a parallelogram.
BabaBlast [244]

Answer:

I believe you are right.

Step-by-step explanation:

All sides seem to be of similar length. The values you put in would make the sides equal so I would go with that one.

5 0
2 years ago
Ken drew a pair of intersecting rays and marked a angle between them.
andre [41]

Answer:

Option 3 is the best option that compares the pair of intersecting rays with the angle

Step-by-step explanation:

The definition of angle says that an angle is a shape that is produced by the intersection of two rays that have a common end point.

A ray is a line segment that has only one end point and is extended infinitely in a unique direction

So Yeah. :) Hope I've helped

6 0
2 years ago
Alisons mom was baking cupcakes for the school's bake sale.Each of her cupcake pans can hold up to 8 cupcakes.If she has 9 cupca
Ivan
The answer is 72!!


- hope this helped!!!
8 0
3 years ago
write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o
Alenkinab [10]
\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\
f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}
\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see,
 
\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
5 0
3 years ago
Use the equation p = 831 where p = pressure and
Inga [223]

Answer:

The lower the volume, the higher the pressure.

Step-by-step explanation:

Volume and pressure are inverse to each other -- so the more pressure, the less volume, and vice versa. Think of it like this: if you were squished into a tiny room, there would be a lot of pressure on you, and not a lot of volume to move in!

You can also think of it numerically. The higher the V in that equation (the higher the denominator) the lower the p in the equation.

6 0
2 years ago
Read 2 more answers
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