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3 years ago

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an athlete runs 8 miles from their house to the store on a path. the athlete then runs to a point m miles from their house on th

e same path. the athlete decides to finish the run by returning to the store. the athlete ran a total of 16 miles. formulate an absolute value equation to represent this situation. then solve the equation.

1 answer:

Nookie1986 [14]3 years ago

6 0

9. Which of the following is a mental benefit of exercise

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16% is the downpayment forn9,000

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3 years ago

50 points!!!Adam recorded the number of flower blooms on each of his ten rose bushes. 9, 10, 4, 12, 15, 17, 18, 10, 12, 13If he

lyudmila [28]

Answer:

12

Step-by-step explanation:

9, 10, 4, 12, 15, 17, 18, 10, 12, 13

Putting the numbers from smallest to largest

4,9, 10, 10, 12 12, 13, 15, 17, 18,

The median is the middle number

There are 10 numbers

4,9, 10, 10, 12 12, 13, 15, 17, 18,

The middle number is between the 12's, so it is 12

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4 years ago

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Simplify (ignore my garbage camera quality ....)

monitta

Answer:

C. 3

Step-by-step explanation:

Given expression is:

$({3^{\frac{1}{7}})^7$

We know that the rules of exponents are used to solve these kind of questions.

When there is exponent on exponent like in this question 1/7 has an exponent of 7 , the exponents are multiplied.

So,

$=3^{(7*\frac{1}{7} )}$

The 7's will be cancelled out and remaining power will be 1

$=3^1\\=3$

Hence, option C is correct ..

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3 years ago

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Which number is a solution for the inequality below?

nasty-shy [4]

Answer:

D 90

Step-by-step explanation:

x/4 ≥ 20

Multiply each side by 4

4*x/4 ≥ 20*4

x ≥ 80

The only number greater than or equal to 80 is 90

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3 years ago

Read 2 more answers

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago