Question

What is the electric field produced by this charge at point P, which is on the x-axis, 9.83 mm from the origin

Answer 1

Given :

Distance of point P from the origin is , d = 9.83 mm .

To Find :

The electric field produced by this charge at point P , if charge is placed at origin .

Solution :

Let , charge on origin is q .

Electric field at point P is given by :

$E=\dfrac{kq}{r^2}$    ..... ( 1 )

Here , k is constant , $k=9\times 10^{9}\ N \ m^2/C^2$ .

Putting value of k and r in above equation , we get :

$E=\dfrac{q\times 9\times 10^9}{(9.83\times 10^{-3})^2}\ N/C\\\\E=(9.31\times 10^{13})q\ N/C$

Hence , this is the required solution .