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Circumcenter is where three perpendicular bisectors intersect and incenter is where the three angle bisectors intersect.
Way to find them and the theorems are mentioned below.
Step-by-step explanation:
To find Incenter :
Construct angle bisectors of each angle of the triangle and their intersection point gives the incenter.
To find Circumcenter:
Construct perpendicular bisectors of all sides of triangle and their intersection point gives the circumcenter.
Circumcenter Theorem: It states that the vertices of a triangle are equidistant from the circumcenter.
Incenter Theorem: It states that the incenter is equidistant from the sides of the triangle.
Answer:
The probability that the student answers at least seventeen questions correctly is
.
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of correctly answered questions.
It is provided all the questions have five options with only one correct option.
Then the probability of selecting the correct option is,

There are <em>n</em> = 20 question in the exam.
It is also provided that a student taking the examination answers each of the questions with an independent random guess.
Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.
The probability mass function of <em>X</em> is:

Compute the probability that the student answers at least seventeen questions correctly as follows:


Thus, the probability that the student answers at least seventeen questions correctly is
.
B is the answer to the question
Answer:First make sure your calculator is on the right setting which would be a DEG. Then depending on the problem you would press COS, put whats needed inside the parentheses and close it.
Or if a different kind of problem you would press 2nd on the top of the calculator then Cos and continue the same way as the first one.
Step-by-step explanation: