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2 years ago

What’s the physical properties of a molecular solid, in regards to its physical properties of formation?

1 answer:

7 0

It has a fixed mass
it does not change with the shape of the container
it cannot be compressed
it has fixed atom and molecules and limited to very small displacement
only vibrational motion occur in the molecules of solid .

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Chemistry

Aleks [24]

Answer:

A. High electrical conductivity

Explanation:

solid silver isn't brittle, it has a high melting point, and its not a good insulator.

4 0

2 years ago

Identify the base-conjugate acid pair in this balanced equation:

Elan Coil [88]

<h3><u>Answer;</u></h3>

NH3/NH4+

<h3><u>Explanation;</u></h3>

From the equation;

NH3(aq)+HNO3(aq)→NH4+(aq)+NO3−(aq)

NH3 is the base; while NH4+ is the conjugate acid

HNO3 is the acid; while NO3- is the conjugate base

The conjugate base of a Brønsted-Lowry acid is species that is formed after an acid donates a proton while the conjugate acid of a Brønsted-Lowry base is the species formed after a base accepts a proton.

3 0

3 years ago

Read 2 more answers

Compare the strength of the intermolecular forces in solids liquids and gases

telo118 [61]

Intermolecular forces in solids are strongest than in liquids and gases. Gases have the least strong intermolecular forces. Intermolecular forces are weak and are significant over short distances between molecules (determined by Coulomb’s law). The farther away from the molecules the weaker the intermolecular forces. Since molecules in solids are the closest, the intermolecular force between them as the strongest. Conversely, since gas molecules are farthest apart, the intermolecular forces between them are the weakest.

3 0

3 years ago

Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50

devlian [24]

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C $_{V}$ You can work out C $_{V}$

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC $_{V}$ ∆T

Polyatomic gas: C $_{V}$ = 3R

∆U= nC $_{V}$ ∆T

∆U= 28g x C $_{V}$ x (350K - 58.3K)

∆U = 28C $_{V}$ x 291.7

∆U = 10967.6 x C $_{V}$

5 0

3 years ago

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

concentration 2 = (287 x 1.6) / 412

Simplification

concentration 2 = 459.2 / 412

Result

concentration 2 = 1.11 M

5 0

3 years ago