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scoray [572]
2 years ago
8

PLEASE HELP QUICKLY THANK YOU

Chemistry
2 answers:
tresset_1 [31]2 years ago
7 0

Answer:

A ocean currents! it also can cause seafloor spreading

77julia77 [94]2 years ago
4 0

Answer:

d

Explanation:

I'm not really sure, hope that helps

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2.50 L of a gas at standard temperature and pressure is compressed to 575 mL. What is the new pressure of the gas
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Each square of the periodic table shows information about one element. The square usually shows the element's
omeli [17]
D, all of the above.
7 0
2 years ago
What is the molar mass of just the O in CO2?
Vlad1618 [11]

Answer:

16 g/mol

Explanation:

In CO2, it means we have 1 mole of carbon and 2 moles of oxygen.

However, we want to find the molar mass of just a single mole of oxygen.

Now, from tables of values of elements in electronic configuration, the molar mass of oxygen is usually approximately 16 g/mol.

In essence the molar mass is simply the atomic mass in g/mol

8 0
3 years ago
Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct
allochka39001 [22]

Answer:

B. CO₂ and H₂O.

Explanation:

When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).

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With the above information in mind the correct answer is option B. CO₂ and H₂O.

When the combustion is incomplete, carbon monoxide (CO) is produced as well.

8 0
3 years ago
Read 2 more answers
Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. be sure your answer has the correct number
Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
3 0
3 years ago
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