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ira [324]
3 years ago
10

Using a skeletal structure, give the structure corresponding to the name (s)−3−iodo−2−methylnonane.

Chemistry
1 answer:
lara31 [8.8K]3 years ago
8 0

Explanation:

For the given compound: (s)-3-iodo-2-methylnonane, only third carbon- atom (marked with red dot) is the chiral atom (as it is attached to 4 different substituents), so the configuration will be assigned to this C-atom only.

In assigning the configuration of this compound, the priorities are assigned based on their atomic masses. The lowest priority group ( that is Hydrogen) should lie on the vertical line. But here, it is lying on the horizontal line, so the configuration will be reversed.

The configuration coming out when H is on the horizontal line is R, but the actual configuration will be S.

The structure of the given organic compound is shown in the image attached.

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Answer:

-2

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Thus, calcium loses two electrons to sulfate ion and sulfate ion accepts these electrons to form ionic bond.

Calcium sulfate, CaSO_4 is formed when 2 valence electrons of calcium are loosed and they are gained by sulfate ion.

Ca^{2+}+SO_4^{2-}\rightarrow CaSO_4

Thus, the charge on the sulfate ion is -2.

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3 years ago
what is the main 'impurity' collected with the oil in distillation. PLEASE HELP IM IN END OF YEAR EXAM. II WILL GIVE BRAINLIEST
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Explanation:

5 0
3 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
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disa [49]

Answer:

A

Explanation:

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