Using a skeletal structure, give the structure corresponding to the name (s)−3−iodo−2−methylnonane.
1 answer:
Explanation:
For the given compound: (s)-3-iodo-2-methylnonane, only third carbon- atom (marked with red dot) is the chiral atom (as it is attached to 4 different substituents), so the configuration will be assigned to this C-atom only.
In assigning the configuration of this compound, the priorities are assigned based on their atomic masses. The lowest priority group ( that is Hydrogen) should lie on the vertical line. But here, it is lying on the horizontal line, so the configuration will be reversed.
The configuration coming out when H is on the horizontal line is R, but the actual configuration will be S.
The structure of the given organic compound is shown in the image attached.
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Answer : The percent abundance of the heaviest isotope is, 78 %
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
As we are given that,
Average atomic mass = 48.68 amu
Mass of heaviest-weight isotope = 49.00 amu
Let the percentage abundance of heaviest-weight isotope = x %
Fractional abundance of heaviest-weight isotope =
Mass of lightest-weight isotope = 47.00 amu
Percentage abundance of lightest-weight isotope = 10 %
Fractional abundance of lightest-weight isotope =
Mass of middle-weight isotope = 48.00 amu
Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %
Fractional abundance of middle-weight isotope =
Now put all the given values in above formula, we get:
Therefore, the percent abundance of the heaviest isotope is, 78 %