3 years ago

What is 95°F on the Celsius scale?

Physics

1 answer:

dem82 [27]3 years ago

7 0

It is 35 degrees Celsius

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u is the initial velocity = 10 m/s

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$a = \dfrac{v^2-u^2}{2s} = \dfrac{(0 \text{ m/s})^2-(10 \text{ m/s})^2}{2\times (35\text{ m})} = -1.43\text{ m/s}^2$

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