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Rom4ik [11]
3 years ago
11

6.A motor pulls an 800 kg roller coaster train to the top of a 75 m hill. What is the change in the potential energy of the cars

?
A.5.9 x 10 ⁵ J
B.6.0 x 10 ⁴ J
C.18 x 10 ⁴ J
D.7.5 x 10 ⁵ J

7.Friction converts kinetic energy to which form?
A.potential energy
B.mechanical energy
C.non mechanical energy
D.total energy

8.How much power does a crane need to lift a 200.0 kg mass at a speed of 2.300 m/s?
A. 460W
B. 1962W
C. 4513W
D. 6123W

9.If a 50.0 kg cheetah, initially at rest, runs 274 m north in 8.65 s, what is its momentum?
A.31.7 kg m/s
B.1584 kg m/s
C.490.5 kg m/s
D.118,500 kg m/s

10.What is the kinetic energy of a 0.005 kg raindrop that falls 250 m?
A.4.9J
B.1.25J
C.8.3J
D.5.6J
Physics
1 answer:
polet [3.4K]3 years ago
8 0
6 -b
7-d
8-a
9-d
10-c

hope this helps:)
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Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

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What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?
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K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 =  6 v²

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I hope this answer is correct.

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Rudiy27

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

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