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3 years ago

What is the opposite of negative 6

Mathematics

1 answer:

Greeley [361]3 years ago

5 0

The opposite of -6 is 6 because its a positive version of -6.

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What would you do first to solve 5x−24=6

Alenkasestr [34]

answer: x=6

Step-by-step explanation:

move all terms that don't contain x to the right side and solve.

8 0

4 years ago

Find the equation in slope-intercept form that describes a line through (2, 4) with slope 0

True [87]

Since we already know that the slope is 0, x cancels out in the equation.

y = mx + b → y = b

We just need to find the y-intercept. Using the coordinate (2, 4) we can substitute with y.

4 = b

Hence, the answer is b) y = 4

Hope This Helped! Good Luck!

6 0

3 years ago

I need help on this

Ipatiy [6.2K]

Draw a vertical line at the number 4 on your x axis positive side which is x=4

Then anything on the left of this line you just created at x=4 will be less than 4. But since your inequality is x less than/equal to 4 it includes 4 as well.

5 0

3 years ago

What is 3.57 as a fraction

Ainat [17]

357/100
because .57 is the same as 57 hundriths which translates to 57/100. Now you have 3 and 57/100 and to make thing into an improper fraction you follow these steps.
1. mulitply the whole number (the number in front on the fraction) by the denominator (the lower part of the fraction). In our case, multiply 3 and 100. You get 300.
2. Add your answer to the numorator (the upper part on the fraction). 300 plus 57 equals 357.
3. Use your answer as the new numorator and keep the original denomanator.
Answer: 357/100

3 0

3 years ago

zheka24 [161]

Answer:

The circumference of the smaller circle is:

C = 2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

C(A) = 2*pi*x/3

5 0

3 years ago