Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
Answer:
Both cars convert more kinetic energy to thermal energy.
Explanation:
Given that,
Two cars come to a stop from the same initial speed, one braking gently and the other braking hard.
We know that,
The conservation of energy :
The energy of the system is always constant.
The energy can be change one form to another form.
So, we can say that when both cars come to a stop from the same speed, one braking softly and the other braking strongly then both cars convert more kinetic energy to thermal energy.
Hence, Both cars convert more kinetic energy to thermal energy.
Answer: 219,344.5 j
Explanation:
from the question we have the following parameters
mass of barge (m) = 5 x 10^4 kg
angle of ropes (θ) = 45 degrees
force by each mule (F1) = 1.10 kN = 1100 N
force by each mule (F2) = 1.10 kN = 1100 N
distance (s) = 141 m
work done by the mules = force x cos θ x distance
since we are calculating the force of both mules we have to both mules before we can use in the equation
force = 1100 + 1100 = 2200 N
work done = 2200 x cos (45) x 141
work done = 219,344.5 j
