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dimaraw [331]
2 years ago
8

Every 30,000 miles, __________. replace the brakes vacuum the interior service the automatic transmission (if your car has one)

inspect the trunk latch
Physics
2 answers:
Vinil7 [7]2 years ago
8 0

Every 30,000 miles service the automatic transmission.  

Automobile engine is a very sophisticated internal machine. The heat it generates is very intense and to prevent damage to the engine, a transmission fluid is applied to all the different parts of the transmission. The transmission fluid will make the transmission to be cool and lubricated.

<h2>Further Explanation</h2>

Apart from lubricating the various part of the transmission, transmission fluid also serves other functions, which include:

  • It increase engine speed an temperature range
  • It cleans and protects metal surfaces
  • It enhance engine cooling function.  
  • It reduces operating temperatures when high.

It is highly recommended to change your transmission fluid every 30,000 miles. Changing it every 30,000 miles or 2 to 4 years will enable the transmission to run healthy fluid always. This will lead to a long lasting transmission.

Transmission fluid acts as lubricants for all moving parts in your transmission for optimum performance. Transmission fluid also acts as coolant in vehicles with automatic transmissions.  

There are basically different types of transmission fluids and the type that are used in different Vehicles. The types of transmission to be used in vehicles, primarily depends on the transmission inside.  

Automatic transmission uses automatic transmission fluid but the types of transmission fluid used in manual varies.  

However, these are various types of transmission fluid.

  • Type-F
  • Hypoid Gear Oil
  • Motor Oil
  • Synthetic Fluids
  • Dexron/Mercon
  • HFM Fluids

LEARN MORE:

  • automatic transmission brainly.com/question/4903132
  • transmission brainly.com/question/11663354

KEYWORDS:

  • miles
  • oil
  • automatic transmission
  • fluid
  • machines
  • lubrication
professor190 [17]2 years ago
7 0
The answer is service the automatic transmission. It must be done because more heat is created in an automatic transmission. Automatic transmission fluid actually reduces and breaks down with use. Also, like in a manual transmission, automatic transmission fluid will also become tainted with worn bits of the transmission. If these contaminants are not drained out, they will reduce the life of the transmission.
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3 years ago
A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the ro
fgiga [73]

Answer:

The vibrational frequency of the rope is 5 Hz.

Explanation:

Given;

number of complete oscillation of the rope, n = 20

time taken to make the oscillations, t = 4.00 s

The vibrational frequency of the rope is calculated as follows;

Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz

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2 years ago
A crate with a mass of 110 kg glides through a space station with a speed of 4.0 m/s. An astronaut speeds it up by pushing on it
Darina [25.2K]

Answer:

The final speed of the crate after the astronaut push to slow it down is 4.50 m/s

Explanation:

<u>Given:  </u>

The crate has mass m = 110 kg and an initial speed vi = 4 m/s.  

<u>Solution  </u>

We are asked to determine the final speed of the crate. We could apply the steps for energy principle update form as next  

Ef=Ei+W                                                 (1)

Where Ef and Ei are the find and initial energies of the crate (system) respectively. While W is the work done by the astronaut (surrounding).  

The system has two kinds of energy, the kinetic energy which associated with its motion and the rest energy where it has zero speed. The summation of both energies called the particle energy. So, equation (1) will be in the form  

(Kf + mc^2) = (KJ+ mc^2)                       (2)  

Where m is the mass of crate, c is the speed of light which equals 3 x 10^8 m/s and the term mc^2 represents the energy at rest and the term K is the kinetic energy.  

In this case, the rest energy doesn't change so we can cancel the rest energy in both sides and substitute with the approximate expression of the kinetic energy of the crate at low speeds where K = 1/2 mv^2 and equation (2) will be in the form

(1/2mvf^2+mc^2)=(1/2mvi^2 +mc^2)+W

1/2mvf^2=1/2mvi^2+W                              (3)

Now we want to calculate the work done on the crate to complete our calculations. Work is the amount of energy transfer between a source of an applied force and the object that experiences this force and equals the force times the displacement of the object. Therefore, the total work done will be given by  

W = FΔr                                                      (4)  

Where F is the force applied by the astronaut and equals 190 N and Δr is the displacement of the crate and equals 6 m. Now we can plug our values for F and Δr to get the work done by the astronaut  

W = F Δr= (190N)(6 m) = 1140 J  

Now we can plug our values for vi, m and W into equation (3) to get the final speed of the crate  

1/2mvf^2=1/2mvi^2+W

vf=5.82 m/s

This is the final speed of the first push when the astronaut applies a positive work done. Then, in the second push, he applies a negative work done on the crate to slow down its speed. Hence, in this case, we could consider the initial speed of the second process to be the final speed of the first process. So,  

vi' = vf

In this case, we will apply equation (3) for the second process to be in the

1/2mvf^2=1/2mvi'^2+W'                                 (3*)

The force in the second process is F = 170 N and the displacement is 4 m. The force and the displacement are in the opposite direction, hence the work done is negative and will be calculated by  

W'= —F Δr = —(170N)(4 m)= —680J

Now we can plug our values for vi' , m and W' into equation (3*) to get the final speed of the crate  

1/2mvf'^2=1/2mvi'^2+W'

  vf'=4.50 m/s

The final speed of the crate after the astronaut push to slow it down is 4.50 m/s

7 0
3 years ago
Thought Experiment: A monkey escapes from a zoo and climbs a tree. After failing to entice the monkey down, a zookeeper fires a
Andreyy89

Explanation:

When bullet is shot towards the monkey then let say the distance of monkey from the bullet is "d"

so we can find the time to reach the bullet to the monkey

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\Delta y = v sin\theta (\frac{d}{vcos\theta}) - \frac{1}{2}gt^2

so it is given as

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here if the monkey is initially at height H above the ground at given angle then we can say

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so we can say that

\Delta y = H - \frac{1}{2}gt^2

So if at the same time monkey will fall down then the height of monkey from ground after time "t" is given as

\Delta y = H - \frac{1}{2}gt^2

so here bullet will hit the monkey as both monkey and bullet are at same position.

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