Answer:
a. 12.57 m/s b. 39.5 m/s² c. Her centripetal force is four times her weight.
Explanation:
a. What is Missy's linear speed on the rotor?
Missy's linear speed v = 2πr/T where r = radius = 4.0 m and T = time it takes to complete one revolution = 2.0 s
So, v = 2πr/T
= 2π(4.0 m)/2.0 s
= 4π m/s
= 12.57 m/s
b. What is Missy's centripetal acceleration on the rotor?
Missy's centripetal acceleration, a = v²/r where v = linear velocity = 12.57 m/s and r = radius = 4.0 m
a = v²/r
= (12.57 m/s)²/4.0 m
= 158.01 m²/s² ÷ 4.0 m
= 39.5 m/s²
c. If her mass is 50-Kg, how is the centripetal force compare to her weight?
Her centripetal force F = ma where m = mass = 50 kg and a = centripetal acceleration = 39.5 m/s².
Her weight W = mg where m = mass = 50 kg and g = acceleration due to gravity = 9.8 m/s².
So, comparing her centripetal force to her weight, we have
F/W = ma/mg
= a/g
= 39.5 m/s² ÷ 9.8 m/s²
= 4.03
≅ 4
So her centripetal force is four times her weight.
