New moon or cresant moon i believe
To solve this problem it is necessary to apply the kinematic equations of motion.
By definition we know that the position of a body is given by
![x=x_0+v_0t+at^2](https://tex.z-dn.net/?f=x%3Dx_0%2Bv_0t%2Bat%5E2)
Where
Initial position
Initial velocity
a = Acceleration
t= time
And the velocity can be expressed as,
![v_f = v_0 + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_0%20%2B%20at)
Where,
![v_f = Final velocity](https://tex.z-dn.net/?f=v_f%20%3D%20Final%20velocity)
For our case we have that there is neither initial position nor initial velocity, then
![x= at^2](https://tex.z-dn.net/?f=x%3D%20at%5E2)
With our values we have
, rearranging to find a,
![a=\frac{x}{t^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bx%7D%7Bt%5E2%7D)
![a = \frac{ 401.4}{4.945^2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%20401.4%7D%7B4.945%5E2%7D)
![a = 16.41m/s^2](https://tex.z-dn.net/?f=a%20%3D%2016.41m%2Fs%5E2)
Therefore the final velocity would be
![v_f = v_0 + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_0%20%2B%20at)
![v_f = 0 + (16.41)(4.945)](https://tex.z-dn.net/?f=v_f%20%3D%200%20%2B%20%2816.41%29%284.945%29)
![v_f = 81.14m/s](https://tex.z-dn.net/?f=v_f%20%3D%2081.14m%2Fs)
Therefore the final velocity is 81.14m/s
C. The sun is 400 times farther from Earth than the moon is.
Thank you for posting your question here and Brainly!~
Even though you have not provided answer choices, I believe the answer is whatever letter corresponds with the answer: "It is rubbed with another object, and electrons move onto the rod."
Hope I helped!~ Brainliest appreciated.
Because metric units use the deca system, 1km = 1000m = 100 000cm etc...