Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.
Answer: the answer should be 7
Step-by-step explanation: V=πr2h
3=π·1.52·3
3≈7.06858
you can find the radius for the area of the base 7 by dividing by 
like such 7/3.1459 the squared because remember its in r2 form which give you 1.5 then plug this in for one of two ways to solve A· 1/3 or V=πr2h
Answer:
85
Step-by-step explanation:
Answer:
9600
Step-by-step explanation:
y varies inversely with the square of x
y=k/(x^2)
for some non-zero constant k
y=6 when x=4
6=k/(4^2)
k=96
y=96/(x^2)
x=0.1
y=96/(0.1^2)
y=9600
7h + 6b = 35.50
5h + 6b = 30.50
The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)
5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3
Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50
