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netineya [11]
3 years ago
8

The math test has 15 multiple choice questions, each with 3 answers. If Betty guesses correctly on the first 4 questions,

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0

Answer:

90 percent

Step-by-step explanation:

15 divided by 4 so 3.75 i rounded it and i got 4

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How does knowing multiplication rules help solve problems faster and easier
KengaRu [80]

Answer: It helps because you already know it off the top of your head and you are able to break up a multiplication problem step by step in your head.

Step-by-step explanation:

3 0
3 years ago
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Can someone please help me on 50.
Andrei [34K]
50) MAD=1.6

Follow steps...
<span>To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. Find the absolute value of the difference between each data value and the mean: |data value – mean|. Find the sum of the absolute values of the differences. <span>Divide the sum of the absolute values of the differences by the number of data values.</span></span>
5 0
3 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
2 years ago
Which set of points lies on the the graph of the function.
meriva

Answer:

(0,0), (-1, 1), and (1,-1)

Step-by-step explanation:

If you were to plot all the points they would all end up being on the green line

I hope this helped?

8 0
2 years ago
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joseph and patrick purchase school supplies in the book store. Joseph purchases four notebooks and three pens for $10.65. Patric
natali 33 [55]

I think it is going to be 3.55 for each notebook and 1.9 for each pen

6 0
3 years ago
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