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Licemer1 [7]
3 years ago
15

5 uses of satellite​

Physics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

uses of satellites:

  1. Scientific Investigation
  2. Earth observation - including weather forecasting and tracking storms and pollution
  3. Communications - including satellite television and telephone calls
  4. Navigation - including the Global Positioning System (GPS)
  5. Military - including reconnaissance photography and communications (nuclear weapons are not allowed in space)
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Benny has 20 jellybeans and wants to share with his friends how many will each friend get? there are 5 friends.
trasher [3.6K]

Answer each friend will get 3.33333 repeating if he is included. if only his friends are getting them then each one gets 4

Explanation:

devide 20/6 and 20/5 respectively.

7 0
3 years ago
What human process are carbon sources that are upsetting the balance between CO to update via planets and CO2 released by living
Serhud [2]
The combustion of fossil fuels is releasing more co2 into the atmosphere then what would occur naturally
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3 years ago
In humans, which part of the brain contains 80 percent of its weight? cerebrum cerebellum spiral cord brain stem
scZoUnD [109]
I believe it's the Cerebrum
6 0
3 years ago
A 2.5 m -long wire carries a current of 8.0 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
leva [86]

Answer:

Explanation:

Let the magnetic field be B = B₁i + B₂j + B₃k

Force = I ( L x B )  , I is current , L is length and B is magnetic field .

In the first case

force = - 2.3 j N

L = 2.5 i

puting the values in the equation above

- 2.3 j = 8 [ 2.5 i x ( B₁i + B₂j + B₃k )]

= - 20 B₃ j + 20 B₂ k

comparing LHS and RHS ,

20B₃ = 2.3

B₃ = .115

B₂ = 0

In the second case

L = 2.5 j

Force = I ( L x B )

2.3i−5.6k = 8 ( 2.5 j x (B₁i + B₂j + B₃k )

=  - 20 B₁ k + 20B₃ i

2.3i−5.6k = - 20 B₁ k + 20B₃ i

B₃ = .115

B₁ = .28

So magnetic field B = .28 i + .115 B₃

Part A

x component of B = .28 T

Part B

y component of B = 0

Part C

z component of B = .115 T .

8 0
3 years ago
A weightlifter curls a 30 kg bar, raising it each time a distance of 0.60 m. How many times must he repeat this exercise to burn
Sholpan [36]

Answe

given,

mass of the bar, m = 30 Kg

distance of rise, h = 0.60 m

Assuming the efficiency = 25 %

energy from the pizza slice = 300 C = 1260 kJ

To consume Energy from the pizza bar is to be pulled several number of time.

( energy from pizza ) x (efficiency) = n m g h

n is the number of lift

( 1260 x 10³) x (0.25) = n x 30 x 9.8 x 0.6

n = \dfrac{315\times 10^3}{176.4}

     n = 1786 times.

Weightlifter should lift bar 1786 times to burn off the energy.

8 0
3 years ago
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