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Licemer1 [7]
3 years ago
15

5 uses of satellite​

Physics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

uses of satellites:

  1. Scientific Investigation
  2. Earth observation - including weather forecasting and tracking storms and pollution
  3. Communications - including satellite television and telephone calls
  4. Navigation - including the Global Positioning System (GPS)
  5. Military - including reconnaissance photography and communications (nuclear weapons are not allowed in space)
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The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
salantis [7]

\boxed{\sf \tau=rFsin\theta}

Put values

\\ \rm\hookrightarrow 40=2Fsin40

\\ \rm\hookrightarrow Fsin40=20

\\ \rm\hookrightarrow 0.64F=20

\\ \rm\hookrightarrow F=31.25N

8 0
3 years ago
Will mark as brainlist for only correct answer
Crank

Answer:

low, low

Explanation:

Longer wavelengths will have lower frequencies, and shorter wavelengths will have higher frequencies.

Large amplitude waves contain more energy. The other is frequency, which is the number of waves that pass by each second. If more waves( or more wiggly lines)  pass by, more energy is transferred each second

4 0
3 years ago
is it possible to breed a black haired long tailed retriever? If so, what percentage is possible? PLEASE answer the corrects ans
Pachacha [2.7K]

Answer: it can be considered a genetic mutation with a history of a Golden Retriever in their blood but it is very rare. and there our some black retrievers you can buy too. i hope i helped

Explanation:

6 0
2 years ago
Read 2 more answers
A weather balloon is partially inflated with helium gas to a volume of 2.0 m³. The pressure was measured at 101 kPa and the temp
Yanka [14]

Answer:

4.7 m³

Explanation:

We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2

* Givens :

P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K

( We must always convert the temperature unit to Kelvin "K")

* What we want to find :

V2 = ?

* Solution :

101 × 2 / 300.15 = 40 × V2 / 283.15

V2 × 40 / 283.15 ≈ 0.67

V2 = 0.67 × 283.15 / 40

V2 ≈ 4.7 m³

7 0
2 years ago
An inductor has inductance of 0.260 H and carries a current that is decreasing at a uniform rate of 18.0 mA/s.
nignag [31]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

\epsilon = -L\frac{dI}{dt}

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

\epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V

Therefore, the self-induced emf in this inductor is 4.68 mV.  

I hope it helps you!

6 0
3 years ago
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