When a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
From Newton's third equation of motion,
v^2 = u^2 + 2gh
where,
h is the height of the object or body from ground
u is the initial velocity of the body or object
v is the final velocity of the body or object
g is the acceleration due to gravity
Now, as we know that
Flowerpot is at rest. So, u = 0
g = 9.81m/s^2
h = 36.5m
By substituting all the values, we get
v^2 = 2 × 9.81 × 36.5
= 716.13
v = 26.7m/s
Thus, we concluded that when a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
learn more about Newton's equation of law of motion:
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Answer:
10
Explanation:
But you have to be fat though lol
<h2>
Answer: 10615 nm</h2>
Explanation:
This problem can be solved by the Wien's displacement law, which relates the wavelength 
where the intensity of the radiation is maximum (also called peak wavelength) with the temperature 
of the black body.
In other words:
<em>There is an inverse relationship between the wavelength at which the emission peak of a blackbody occurs and its temperature.</em>
Being this expresed as:
(1)
Where:
is in Kelvin (K)
is the <u>wavelength of the emission peak</u> in meters (m).
is the <u>Wien constant</u>, whose value is 
From this we can deduce that the higher the black body temperature, the shorter the maximum wavelength of emission will be.
Now, let's apply equation (1), finding :
(2)
Finally:
This is the peak wavelength for radiation from ice at 273 K, and corresponds to the<u> infrared.</u>
Fresnel and Fraunhofer diffraction. Fresnel diffraction is produced when light from a point source meets an obstacle, the waves are spherical and the pattern observed is a fringed image of the object. Fraunhofer diffraction occurs with plane wave-fronts with the object effectively at infinity. The pattern is in a particular direction and is a fringed image of the source.
Conducting because it occurs when two objects touch and heat is transferred
