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Ganezh [65]
3 years ago
10

A world-class tennis player can serve a tennis ball at 130 mi/h mi/h (about 58 m/s m/s ). The length of a tennis court is 78 ft

ft . Approximately how long does an opponent have to react from the instant the ball is served until the ball reaches the opponent?.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The time taken is   t = 0.4103 \ s

Explanation:

From the question we are told that

  The  speed is  v  =  130 \  mi/h =  58 \  m/s

   The  length of the tennis court l =  78 \ ft = \frac{78}{3.281}= 23.8 \ m

 Generally the time taken is mathematically represented as

      t =  \frac{ 23.8}{ 58}

=>        t = 0.4103 \ s

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Answer:

1) Any particle moving in a horizontal plane slowed by friction, deceleration = 32 μ

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Explanation:

* Lets revise Newton’s Third Law:

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- Examples:

# 1) A particle moving freely against friction in a horizontal plane

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∵ The frictional force is in opposite direction of the motion

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∴ - μ(g) = a

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# 2) A particle moving under the action of an external force P in a

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∵ ∑ forces in direction of motion = mass × acceleration

∵ The external force = P

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = P - F

∴ P - F = mass × acceleration

- Substitute F by μR

∴ P - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

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∴ P - μ(mg) = ma ⇒ a is the acceleration of motion

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ P - 32μm = ma ⇒ (1)

- divide both side by m

∴ a = (P - 32μm)/m ⇒ divide the 2 terms in the bracket by m

∴ a = P/m - 32μ

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