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Ganezh [65]
3 years ago
10

A world-class tennis player can serve a tennis ball at 130 mi/h mi/h (about 58 m/s m/s ). The length of a tennis court is 78 ft

ft . Approximately how long does an opponent have to react from the instant the ball is served until the ball reaches the opponent?.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The time taken is   t = 0.4103 \ s

Explanation:

From the question we are told that

  The  speed is  v  =  130 \  mi/h =  58 \  m/s

   The  length of the tennis court l =  78 \ ft = \frac{78}{3.281}= 23.8 \ m

 Generally the time taken is mathematically represented as

      t =  \frac{ 23.8}{ 58}

=>        t = 0.4103 \ s

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2 years ago
Can a body possess velocity at the same time in horizontal and vertical directions?​
iogann1982 [59]

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please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c
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Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

   = \sqrt{17.81+19.18}

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

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3 years ago
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