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3 years ago

7

a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac

celeration

1 answer:

Katarina [22]3 years ago

6 0

Answer:

a = change in v / change in time

= (5.2 - 11) / 3.1

= -1.87 m/s^2

Explanation:

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A parcel of land is in the shape of an isosceles triangle. The base has a length of 425 ft.; the other sides, which are of equal

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The answer to your question is 636.6 ft

Explanation:

Data

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angle = 39°

See the picture below

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When you jump from an elevated position you usually bend your knees upon reaching the ground. By doing this, you make the time o

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Answer:

c. about 1/10 as great.

Explanation:

While jumping form a certain height when we bend our knees upon reaching the ground such that the time taken to come to complete rest is increased by 10 times then the impact force gets reduced to one-tenth of the initial value when we would not do so.

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$m=$ mass of the person jumping

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3 years ago