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sesenic [268]
3 years ago
7

a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac

celeration
Physics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

a = change in v / change in time

= (5.2 - 11) / 3.1

= -1.87 m/s^2

Explanation:

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T = 3.5 secs

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7 0
3 years ago
What number on this diagram refers to the tick marks for the dependent variable?
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3 years ago
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5 0
3 years ago
A light ray moving at a 54.3 deg
MrMuchimi

Answer:

45.25^{\circ}

Explanation:

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