Explanation:
a) We need to write down first Newton's 2nd law as applied to the given system. The equations of motion for the x- and y-axes can be written as follows:
From Eqn(2), we see that
so using Eqn(3) on Eqn(1), we get
Solving for the acceleration, we see that
b) Now that we have the acceleration, we can now solve for the velocity of the crate at the bottom of the plane. Using the equation
Since the crate started from rest, 
Thus our equation reduces to
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
The attractive force that keeps the nucleus together is called nucleus force.
<span>The nucleus becomes increasingly more stable upon the addition of nucleons up to iron-56.
</span>So, as the size of the nucleus increase more iron 56 are needed.
Iron-56<span> (</span><span>56Fe</span><span>) is the most common isotope of </span><span>iron.</span>
The nucleus is the center of an atom.
