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Anni [7]
3 years ago
10

A free-falling golf ball strikes the ground and exerts a force on it. Which sentences are true about this situation? A golf ball

striking the ground is a collision. The ground exerts an equal force on the golf ball. The ground doesn’t exert a force on the golf ball. The force is zero because the golf ball has little mass.
Physics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer:

The ground exerts an equal force on the golf ball

Explanation:

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

In this problem, object A is the golf ball while object B is the ground, so we can say that:

- the golf ball exerts a force on the ground

- the ground exerts an equal and opposite force on the golf ball

Serga [27]3 years ago
5 0
THe ground exerts an equal force on the golf ball

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eimsori [14]

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Explanation:

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What happens if the breakdown voltage is exceeded.
s2008m [1.1K]

Answer:

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7 0
2 years ago
In boxing, the use of 16-ounce gloves rather than 12-ounce gloves reduces the chance of injury because the force is distributed
mr Goodwill [35]

Answer:

true

Explanation:

Here we have assumed that increasing the mass of a glove will increase the surface area.

Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by

P=\dfrac{F}{A}

where

F = Force

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So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.

Hence, the statement is true.

5 0
3 years ago
Sharp claws in wild animals is an example of which type of adaptation?
Sati [7]

Answer:

Structural adaptation

Explanation:

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3 0
3 years ago
Round your answers to one decimal place.this parallel circuit has two resistors at 15 and 40 ohms. what is the total resistance?
lubasha [3.4K]
1) The equivalent resistance of two resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}
so in our problem we have
\frac{1}{R_{eq}} =  \frac{1}{15 \Omega}+ \frac{1}{40 \Omega}=0.092 \Omega^{-1}
and the equivalent resistance is
R_{eq} =  \frac{1}{0.092 \Omega^{-1}}=10.9 \Omega

2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
I= \frac{V}{R_{eq}}= \frac{12 V}{10.9 \Omega}=1.1 A
4 0
3 years ago
Read 2 more answers
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