The orbital radius is: 
Explanation:
The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.
For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:
where
G is the gravitational constant
M is the mass of the planet
m is the mass of the satellite
r is the radius of the orbit
v is the speed of the satellite
Re-arranging the equation, we find:
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6x8 = 48 feet
you can jump 48 feet on the moon
Answer:
Er = 108 [J]
Explanation:
To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.
200 - 44 - 48 = Er
Where:
Er = remaining energy [J]
Er = 108 [J]
Applications of Gas Law in Real Life. A torch used to heat up the and rise the air temperature inside the balloon. This cause the air volume inside the balloon to increased and becoming less dense than the surrounding air. ... The air in the ears will change its volume then causes yours ears to pop due to the strain.
Answer:
(a) The density of the object is 316/343 × the density of the oil
(b) The fraction of oil displaced after immersing the object is 0.461 of the oil volume
Explanation:
(a) The volume, V of a cone of height, h and base diameter, D = 2×r is given by the following equation;
The volume of the object is therefore;
Where 6 cm is above the oil level we have;
above the oil level
Therefore, volume of the oil displaced = 
cm³ = 216.11 cm³
The density of the object is thus;
The density of the object = 316/343 × the density of the oil.
(b) The volume of the oil = 2 × Volume of the object = 
The fraction of the volume displaced, x, after immersing the object is given as follows;
The fraction of oil displaced after immersing the object = 0.461 of the volume of the oil
