Calculate the total mass of these letters in grams (mxe=131.29amu)
2 answers:
The total mass of 131.29 amu
= 2,196.10⁻²² grams
<h3><em>Further explanation</em></h3>Inside the atom consists of a nucleus containing 3 basic particles namely protons and neutrons, while electrons move around the nucleus.
The mass number is not the same as the atomic mass. The mass number is the number of protons and neutrons in one atom. While the atomic mass is a number that expresses the mass of one atom.
Atomic mass is expressed in special units, namely atomic mass units because the atomic mass is very small if expressed in units of grams or milligrams
This atomic unit uses the standard atomic mass, that is, the C-12 isotope
1 C-12 atom = 12 atomic mass units
1 atomic mass unit = 1/12 x mass 1 atom C-12
The mass of 1 proton is equal to the mass of 1 neutron, equal to 1 atomic mass unit and electrons have a smaller mass than both.
electron mass = 9.11.10⁻²⁸ g
proton mass = 1.6726.10⁻²⁴ g
neutron mass = 1,675.10⁻²⁴ g
The proton mass is considered to be equal to 1 atomic mass unit and a neutron which has a slightly larger mass is also considered to be equal to 1 atomic mass unit
1 unit of atomic mass (amu) = 1.6726.10⁻²⁴ g
So if there are 131.29 amu, you can convert them into
= 131.29 x 1.6726.10⁻²⁴ g
= 219,595.10⁻²⁴
= 2,196.10⁻²² grams
<h3><em>Learn more</em></h3>
subatomic particles in an atom
the three particles of an atom
neutrons
the mass, charge, and location of protons, neutrons, and electrons in atoms brainly.com/question/3294412
statement about subatomic particles
The subatomic particle that has the least mass
Keywords: protons, neutrons, electrons, subatomic particles,
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Answer:
The frequency of sound heard by the boy is 1181 Hz.
Explanation:
Given that,
Frequency of sound from alarm
Speed = -8.25 m/s
Negative sign show the boy riding away from the car
Speed of sound = 343
We need to calculate the heard frequency
Using formula of frequency
Where, = frequency of source
= speed of observer
= speed of source
= speed of sound
Put the value into the formula
here, source is at rest
Hence, The frequency of sound heard by the boy is 1181 Hz.