3 years ago

The price of an item has been reduced by 80%. The original price was $35. What is the price of the item now?

Mathematics

1 answer:

Tcecarenko [31]3 years ago

7 0

Answer:it’s 28 or 7

Step-by-step explanation:

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Work out the area of a rectangle with base, b = 20mm and perimeter, P = 60mm.

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base+perimeter

20mm+60mm

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3 years ago

Carmen participated in a read-a-thon. Mr.Cole pledged $4.00 per book and gave Carmen $44.How many books did Carmen read?

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She read 11 books because 44 divided by 4 its 11$

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2 years ago

Show your work with long division please

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Answer:

Step-by-step explanation:

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70/11 = 6, so 0.6, remainder is 4, add 0

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<h3>The answer is 0.63 bar notation on both 6 and 3</h3>

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3 years ago

You are driving in Canada and the speed limit is 110 kph (kilometers per hour). How fast is that in mph (miles per hour)?

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2 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

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3 years ago