Answer:
d. 100.0 J
Explanation:
To solve this problem we must use the theorem of work and energy conservation. This tells us that the mechanical energy in the final state is equal to the mechanical energy in the initial state plus the work done on a body. In this way we come to the following equation:
E₁ + W₁₋₂ = E₂
where:
E₁ = mechanical energy at state 1. [J] (units of Joules)
E₂ = mechanical energy at state 2. [J]
W₁₋₂ = work done from 1 to 2 [J]
We have to remember that mechanical energy is defined as the sum of potential energy plus kinetic energy.
The energy in the initial state is zero, since there is no movement of the hockey puck before imparting force. E₁ = 0.
The Work on the hockey puck is equal to:
W₁₋₂ = 100 [J]
100 = E₂
Since the ice rink is horizontal there is no potential energy, there is only kinetic energy
Ek = 100 [J]
It can be said that the work applied on the hockey puck turns into kinetic energy
Just because the book is moving doesn't tell you anything about the forces on it, or even whether there ARE any.
Just look at Newton's first law of motion, and this time, let's try and THINK about it too. It says something to the effect that any object continues in constant, uniform MOTION ..... UNLESS acted on by an external force.
Answer:
Complete the following table. Be sure to include units in your answer.
Explanation:
all you have to do is mautiply them
Answer: 53 m
Explanation:
Work = Force × Displacement
W= F s cosΘ
Where, s is the displacement and F is the force. Θ is the angle between force and displacement
F cosθ is the component of force acting in the horizontal direction.
The air pump applies F = 150 N force at an angle Θ = 45°
W = 5600 J
⇒s = W/F cosθ
Thus, the horizontal distance the water bottle rocket travels is 53 m
