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irakobra [83]
3 years ago
7

Joe places two solid objects in contact with each other.

Physics
1 answer:
Tasya [4]3 years ago
5 0

Answer:

B. temperature of the objects

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100.0 J of work accelerates a 0.500 kg hockey puck across an ice rink (a frictionless
Olegator [25]

Answer:

d. 100.0 J

Explanation:

To solve this problem we must use the theorem of work and energy conservation. This tells us that the mechanical energy in the final state is equal to the mechanical energy in the initial state plus the work done on a body. In this way we come to the following equation:

E₁ + W₁₋₂ = E₂

where:

E₁ = mechanical energy at state 1. [J] (units of Joules)

E₂ = mechanical energy at state 2. [J]

W₁₋₂ = work done from 1 to 2 [J]

We have to remember that mechanical energy is defined as the sum of potential energy plus kinetic energy.

The energy in the initial state is zero, since there is no movement of the hockey puck before imparting force. E₁ = 0.

The Work on the hockey puck is equal to:

W₁₋₂ = 100 [J]

100 = E₂

Since the ice rink  is horizontal there is no potential energy, there is only kinetic energy

Ek = 100 [J]

It can be said that the work applied on the hockey puck turns into kinetic energy

6 0
3 years ago
HELP ASAP How are the bars in barred spiral galaxies thought to have formed?
sergey [27]

Answer:

D. slow evolution

Explanation:

8 0
3 years ago
A book is sliding along a desk top. Because the book is in motion ,you know that the forces acting on the book are A. Balanced B
Virty [35]
Just because the book is moving doesn't tell you anything about the forces on it, or even whether there ARE any.

Just look at Newton's first law of motion, and this time, let's try and THINK about it too. It says something to the effect that any object continues in constant, uniform MOTION ..... UNLESS acted on by an external force.
4 0
4 years ago
Complete the following table. Be sure to include units in your answer.
mel-nik [20]

Answer:

Complete the following table. Be sure to include units in your answer.

Explanation:

all you have to do is mautiply them

6 0
3 years ago
An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the roc
Alchen [17]

Answer: 53 m

Explanation:

Work = Force × Displacement

W= F s cosΘ

Where, s is the displacement and F is the force. Θ is the angle between force and displacement

F cosθ is the component of force acting in the horizontal direction.

The air pump applies F = 150 N force at an angle Θ = 45°

W = 5600 J

⇒s = W/F cosθ

\Rightarrow s =\frac{5600 J}{150\times cos 45^o}\approx 53 m

Thus, the horizontal distance the water bottle rocket travels is 53 m

8 0
3 years ago
Read 2 more answers
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