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MariettaO [177]
3 years ago
7

Your crew can pave two driveways in a day. You work five days per week but take off 2 weeks each year for holidays and vacations

.How many driveways could your crew pave in a year?
Mathematics
1 answer:
k0ka [10]3 years ago
5 0
According to Philippine Payroll Regulations and Information, there will be a total of 247 working days for all employees working from Mondays to Fridays and considered Saturdays and Sundays as rest days. If the two weeks off is referring to employees working days only, it means employee can file a leave for 14 equivalent days off. Computations will be Total driveways= (247 days-14 days off) * 2 driveways per day and the answer is 466 driveways.
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Answer:

La cantidad de dinero adeuda al final de los dos procesos es $1450

Step-by-step explanation:

Los parámetros del proceso son;

La cantidad ahorrada para comprar ropa = $2,000

La cantidad pagada por la ropa = $2600

La cantidad prestada a un amigo = $650

La cantidad adeuda por teléfono celular durante 3 meses = $250

Deje que 'C', represente la suma de las transacciones anteriores, tenemos;

∴ C = 2,000 - 2,600 - 650 - 200 = -1,450

La suma de las transacciones anteriores, C = -$1,450

Por lo tanto, al final de los dos procesos, la cantidad de dinero adeuda es C = $1,450

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
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Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

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