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ira [324]
4 years ago
11

AM radio signals have frequencies between 550 kHz and 1600 kHz (kilohertz) and travel with a speed of 3.0Ã108m/s. What are the w

avelengths of these signals?
Physics
1 answer:
Westkost [7]4 years ago
5 0

Answer:

The wavelength of these signals is as follow:

  • Wavelength of 550 kHz is 545.45 m
  • Wavelength of 1600 kHz is 187.5 m

Explanation:

Given that:

Frequency = 550 kHz & 1600 kHz

Velocity = 3.0 x 10⁸ m/s

As we know that frequency is expressed by the following equation:

  • Frequency = Velocity / Wavelength ---- (1)

For 550 kHz:

The equation can be rearranged as

Wavelength = Velocity / Frequency

Wavelength = (3.0 x 10⁸ m/s) / (550 x 1000 Hz)

Wavelength = 545.45 m

For 1600 kHz:

Wavelength = Velocity / Frequency

Wavelength = (3.0 x 10⁸ m/s) / (1600 x 1000 Hz)

Wavelength = 187.5 m

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If a seismic wave has a period of 0.0202s, find the frequency of the wave.
maw [93]

Answer:

49.5 Hz.

Explanation:

From the question given above, the following data were obtained:

Period (T) = 0.0202 s

Frequency (f) =?

The frequency and period of a wave are related according to the following equation:

Frequency (f) = 1 / period (T)

f = 1/T

With the above formula, we can obtain the frequency of the wave as follow:

Period (T) = 0.0202 s

Frequency (f) =?

f = 1/T

f = 1/0.0202

f = 49.5 Hz

Therefore the frequency of the wave is 49.5 Hz.

7 0
3 years ago
When a potential difference of 154 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge d
tester [92]

Answer:

4.7\mu m

Explanation:

We are given that

Potential difference=V=154 V

Surface charge density=\sigma=29nC/m^2=29\times 10^{-5} C/m^2

Using 1 nC/cm^2=10^{-5} C/m^2

We know that

C=\frac{\epsilon_0A}{d}=\frac{Q}{V}=\frac{\sigma A}{V}

d=\frac{\epsilon_0V}{\sigma}

Where

\epsilon_0=8.85\times 10^{-12}C^2/Nm^2

Using the formula

d=\frac{8.85\times 10^{-12}\times 154}{29\times 10^{-5}}

d=4.7\times 10^{-6} m=4.7\mu m

Using 1\mu m=10^{-6} m

Hence, the spacing between the plates=4.7\mu m

3 0
3 years ago
A proton with charge 1.602 x 10^-19 C moves at a speed of 300 m/s in a magnetic field at an angle of 65 degrees. If the strength
soldi70 [24.7K]

Answer:

F_m= 8.28 \times 10^{-16} N

Explanation:

The magnitude of the force is F_m=evB\sin\theta\\\implies F_m=1.602 \times 10^{-19}\times 300\times 19\times\sin 65^0= 8.28 \times 10^{-16} N

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3 years ago
How much force do you push down on the Earth with? (Hint: 1kg is about 2 pounds).​
Gennadij [26K]

Answer: 100lbs

Explanation: The Earth pushes you down at 100lbs, so you push down the earth by 100lbs which is enough to keep you firmly attached to the ground and not allow you to jump more than a couple of feet.

3 0
3 years ago
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30 points! Please answer at least one and how you found it! :)
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