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stira [4]
3 years ago
12

How much force is needed to accelerate a 68 kilogram skier at a rate of 1.2m/sec

Physics
2 answers:
xxMikexx [17]3 years ago
8 0

Let's use Newton's 2nd law of motion:

                                     Force = (mass) x (acceleration)

                                     Force = (68 kg) x (1.2 m/s²) =  81.6 newtons .

labwork [276]3 years ago
5 0
f=m*a

68*1.2=81.6

f=81.6
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The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr
WARRIOR [948]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y_n= \frac{n \lambda D}{a} (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
D=37.0 cm=0.37 m
\lambda=530 nm=5.3 \cdot 10^{-7} m
while the distance between the first and the fifth minima is
y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m (2)

If we use the formula to rewrite y_5, y_1, eq.(2) becomes
\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m
Which we can solve to find a, the width of the slit:
a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}=  1.57 \cdot 10^{-3} m=1.57 mm

7 0
3 years ago
How many board feet of lumber are needed assuming 200 lin. Ft. of 2""x 6"" lumber a. 12 b. 16.67 c. 120 d. 200
Svetach [21]

Answer:

B) 16.67

Explanation:

If the dimension of one lumber is 2" × 6", the total area of one lumber will be 12inch²

If the total board feet of lumber there is 200in, therefore the total board of lumber that will be needed is 200/12 which gives 16.67 lumbers

4 0
3 years ago
suppose the same amount of heat is applied to two bars. they have the same mass, but experience different changes in temperature
Andreyy89

If both bars are made of a good conductor, then their specific heat capacities must be different. If both are metals, specific heat capacities of different metals can vary by quite a bit, eg, both are in kJ/kgK, Potassium is 0.13, and Lithium is very high at 3.57 - both of these are quite good conductors.

If one of the bars is a good conductor and the other is a good insulator, then, after the surface application of heat, the temperatures at the surfaces are almost bound to be different. This is because the heat will be rapidly conducted into the body of the conducting bar, soon achieving a constant temperature throughout the bar. Whereas, with the insulator, the heat will tend to stay where it's put, heating the bar considerably over that area. As the heat slowly conducts into the bar, it will also start to cool from its surface, because it's so hot, and even if it has the same heat capacity as the other bar, which might be possible, it will eventually reach a lower, steady temperature throughout.

4 0
3 years ago
Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h
Gelneren [198K]

Answer: W = 1.04.10^{-20} J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

W=q.\Delta V

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = 1.6.10^{-19} C

To determine work in joules, potential has to be in Volts, so:

\Delta V=65.10^{-3}V

Then, work is

W=1.6.10^{-19}.65.10^{-3}

W=1.04.10^{-20}

To move a potassium ion from the exterior to the interior of the cell, it is required W=1.04.10^{-20}J of energy.

8 0
3 years ago
Two long, straight wires are separated by a distance of 9.15 cm . One wire carries a current of 2.79 A , the other carries a cur
Dafna1 [17]

Answer:

The force is the same

Explanation:

The force per meter exerted between two wires carrying a current is given by the formula

\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}

where

\mu_0 is the vacuum permeability

I_1 is the current in the 1st wire

I_2 is the current in the 2nd wire

r is the separation between the wires

In this problem

I_1=2.79 A\\I_2=4.36 A\\r = 9.15 cm = 0.0915 m

Substituting, we find the force per unit length on the two wires:

\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(2.79)(4.36)}{2\pi (0.0915)}=2.66\cdot 10^{-5}N

However, the formula is the same for the two wires: this means that the force per meter exerted on the two wires is the same.

The same conclusion comes out  from Newton's third law of motion, which states that when an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A (action-reaction). If we apply the law to this situation, we see that the force exerted by wire 1 on wire 2 is the same as the force exerted by wire 2 on wire 1 (however the direction is opposite).

3 0
3 years ago
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