3 years ago

How much force is needed to accelerate a 68 kilogram skier at a rate of 1.2m/sec

2 answers:

8 0

Let's use Newton's 2nd law of motion:

Force = (mass) x (acceleration)

Force = (68 kg) x (1.2 m/s²) = 81.6 newtons .

5 0

$f=m*a$

68*1.2=81.6

$f=81.6$

You might be interested in

Rom4ik [11]

Everything dies because it’s to extreme

4 0

3 years ago

cricket20 [7]

They are made of rocks

7 0

3 years ago

Alexandra [31]

Answer:

138.18 minutes

Explanation:

$L_v$ = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

$Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal$

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

$55\times N=45600\\\Rightarrow N=\frac{45600}{55}$

Each cycle takes 10 seconds so the total time would be

$\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes$

The total time taken to freeze 138.18 minutes

6 0

3 years ago

RoseWind [281]

Answer:

1784/223 = 8:1

Explanation:

3 0

3 years ago

ra1l [238]

It's D) valid and testable.

6 0

4 years ago