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Nezavi [6.7K]
3 years ago
10

PLEASE HELP!!!!

Chemistry
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

<u></u>

  • <u>35ºC</u>

Explanation:

You need the specif heat capacities of both cobalt and lead.

  • Specific heat of cobalt: 0.42 J/g.ºC
  • Specific heat of lead: 0.13 J/g.ºC

When the two sheets reach the thermal equilibrium their temperatures are equal.

You can use the equations for the thermal heat to find the equilibrium temperature:

Thermal heat released by the hot sheet, lead:

  • Q = m × C × ΔT
  • Q = 16.6 kg × 0.13J/g.ºC × (63ºC - T)

Thermal heat absorbed by the cold sheet, cobalt:

  • Q = m × C × ΔT
  • Q = 5.78 kg × 0.42J/g.ºC × (T - 11ºC)

Equal the two equations to solve for T:

  • 16.6 kg × 0.13J/g.ºC × (63ºC - T) = 5.78kg × 0.42J/g.ºC × (T - 11ºC)

I remove the units for easier handling:

  • 135.954 - 2.158T = 2.4276T - 26.7036
  • 4.5856T = 162.6576
  • T = 35.47ºC

Round to 2 significant figures: 35ºC ← answer

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Answer: 7 atm

Explanation:

According to Dalton's Law, the total pressure is the sum of all the individual gas pressures

Hence, Ptotal = P1 + P2 + P3

Since, Gas A = 2 atm

Gas B = 1 atm

Gas B = 4 atm

Ptotal = (2 + 1 + 4) atm

Ptotal= 7 atm

Thus, the total pressure of the gas mixture is 7 atmosphere.

3 0
3 years ago
Single replacement reactions: a piece of zinc is added to cadmium chlorate solution
slamgirl [31]

Explanation:

This is feasible single displacement chemical reaction. In this reaction, Zinc displaces cadmium from the chlorate solution:

       Zn + Cd(ClO₃)₂ →  Zn(ClO₃)₂ + Cd

A single displacement reaction is a reaction in which one specie replaces another.

The main driving force in this kind of reaction is the position of the displacing species in the activity series.

In the series, metals that are higher up are more reactive and they will displace the lower ones from solution.

Cadmium is lower in the series and Zn is higher up.

Zn is more reactive than Cd and will displace it form the solution and it gives the expression:

   Zn + Cd(ClO₃)₂ →  Zn(ClO₃)₂ + Cd

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7 0
4 years ago
Sodium metal and water react to create sodium hydrogen and hydrogen gas through the unbalanced equation.
Maurinko [17]

Answer:

Theoretical yield = 2.5 g

Explanation:

Given data:

Mass of sodium = 79.7 g

Mass of water = 45.3 g

Theoretical yield of hydrogen gas = ?

Solution:

Chemical equation:

2Na + 2H₂O → 2NaOH + H₂

Number of moles of sodium:

Number of moles = mass/ molar mass

Number of moles = 79.7 g / 23 g/mol

Number of moles = 3.5 mol

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45.3 g / 18g/mol

Number of moles = 2.5 mol

Now we will compare the moles of hydrogen gas with water and sodium.

                        H₂O           :             H₂

                           2             :              1

                          2.5           :            1/2×2.5 =1.25 mol

                     

                           Na           :              H₂

                             2            :               1

                           3.5           :             1/2×3.5 =1.75 mol

water will be limiting reactant.

Theoretical yield:

Mass = number of moles × molar mass

Mass =  1.25 mol  × 2 g/mol

Mass = 2.5 g

8 0
3 years ago
Write the precipitation reaction for chromium(III) nitrate in aqueous solution: Use the pull-down menus to specify the state of
Licemer1 [7]

Answer:

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6 0
3 years ago
Suppose that 3.33 g of acetone at 25.0 °C condenses on the surface of a 44.0-g block of aluminum that is initially at 25 °C. If
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Answer:

68.6 °C

Explanation:

From conservation of energy, the heat lost by acetone, Q = heat gained by aluminum, Q'

Q = Q'

Q = mL where Q = latent heat of vaporization of acetone, m = mass of acetone = 3.33 g and L = specific latent heat of vaporization of acetone = 518 J/g

Q' = m'c(θ₂ - θ₁) where m' = mass of aluminum = 44.0 g, c = specific heat capacity of aluminum = 0.9 J/g°C, θ₁ = initial temperature of aluminum = 25°C and θ₂ = final temperature of aluminum = unknown

So, mL = m'c(θ₂ - θ₁)

θ₂ - θ₁ = mL/m'c

θ₂ = mL/m'c + θ₁

substituting the values of the variables into the equation, we have

θ₂ = 3.33 g × 518 J/g/(44.0 g × 0.9 J/g°C) + 25 °C

θ₂ = 1724.94 J/(39.6 J/°C) + 25 °C

θ₂ = 43.56 °C + 25 °C

θ₂ = 68.56 °C

θ₂ ≅ 68.6 °C

So, the final temperature (in °C) of the metal block is 68.6 °C.

5 0
3 years ago
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