Answer: 7 atm
Explanation:
According to Dalton's Law, the total pressure is the sum of all the individual gas pressures
Hence, Ptotal = P1 + P2 + P3
Since, Gas A = 2 atm
Gas B = 1 atm
Gas B = 4 atm
Ptotal = (2 + 1 + 4) atm
Ptotal= 7 atm
Thus, the total pressure of the gas mixture is 7 atmosphere.
Explanation:
This is feasible single displacement chemical reaction. In this reaction, Zinc displaces cadmium from the chlorate solution:
Zn + Cd(ClO₃)₂ → Zn(ClO₃)₂ + Cd
A single displacement reaction is a reaction in which one specie replaces another.
The main driving force in this kind of reaction is the position of the displacing species in the activity series.
In the series, metals that are higher up are more reactive and they will displace the lower ones from solution.
Cadmium is lower in the series and Zn is higher up.
Zn is more reactive than Cd and will displace it form the solution and it gives the expression:
Zn + Cd(ClO₃)₂ → Zn(ClO₃)₂ + Cd
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Answer:
Theoretical yield = 2.5 g
Explanation:
Given data:
Mass of sodium = 79.7 g
Mass of water = 45.3 g
Theoretical yield of hydrogen gas = ?
Solution:
Chemical equation:
2Na + 2H₂O → 2NaOH + H₂
Number of moles of sodium:
Number of moles = mass/ molar mass
Number of moles = 79.7 g / 23 g/mol
Number of moles = 3.5 mol
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45.3 g / 18g/mol
Number of moles = 2.5 mol
Now we will compare the moles of hydrogen gas with water and sodium.
H₂O : H₂
2 : 1
2.5 : 1/2×2.5 =1.25 mol
Na : H₂
2 : 1
3.5 : 1/2×3.5 =1.75 mol
water will be limiting reactant.
Theoretical yield:
Mass = number of moles × molar mass
Mass = 1.25 mol × 2 g/mol
Mass = 2.5 g
Answer:
Nitrate is considered SOLUBLE
Explanation:
please kindly refer to attachment for the step by step solution of the given problem.
Answer:
68.6 °C
Explanation:
From conservation of energy, the heat lost by acetone, Q = heat gained by aluminum, Q'
Q = Q'
Q = mL where Q = latent heat of vaporization of acetone, m = mass of acetone = 3.33 g and L = specific latent heat of vaporization of acetone = 518 J/g
Q' = m'c(θ₂ - θ₁) where m' = mass of aluminum = 44.0 g, c = specific heat capacity of aluminum = 0.9 J/g°C, θ₁ = initial temperature of aluminum = 25°C and θ₂ = final temperature of aluminum = unknown
So, mL = m'c(θ₂ - θ₁)
θ₂ - θ₁ = mL/m'c
θ₂ = mL/m'c + θ₁
substituting the values of the variables into the equation, we have
θ₂ = 3.33 g × 518 J/g/(44.0 g × 0.9 J/g°C) + 25 °C
θ₂ = 1724.94 J/(39.6 J/°C) + 25 °C
θ₂ = 43.56 °C + 25 °C
θ₂ = 68.56 °C
θ₂ ≅ 68.6 °C
So, the final temperature (in °C) of the metal block is 68.6 °C.
